Answer:
the velocity of the boats after the collision is 4.36 m/s.
Explanation:
Given;
mass of fish, m₁ = 800 kg
mass of boat, m₂ = 1400 kg
initial velocity of the fish, u₁ = 12 m/s
initial velocity of the boat, u₂ = 0
let the final velocity of the fish-boat after collision = v
Apply the principle of conservation of linear momentum for inelastic collision;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
800 x 12 + 1400 x 0 = v(800 + 1400)
9600 = 2200v
v = 9600/2200
v = 4.36 m/s
Therefore, the velocity of the boats after the collision is 4.36 m/s.
The answer is False, pls. mark me the brainliest if I’m right. THX
Answer: Find an answer to your question given A=125.0=0.4 and 25.0=0.1 calculate A-B
Explanation:
The answer is b) force exponerse by charge in electric field
Answer:
where L is the length of the ramp
Explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of
We can use the following equation of motion to find out the final velocity of the book after sliding L m:
where v m/s is the final velocity, 
= 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and 
is the distance traveled:
