Let's be clear: The plane's "395 km/hr" is speed relative to the
air, and the wind's "55 km/hr" is speed relative to the ground.
Before the wind hits, the plane moves east at 395 km/hr relative
to both the air AND the ground.
After the wind hits, the plane still maintains the same air-speed.
That is, its velocity relative to the air is still 395 km/hr east.
But the wind vector is added to the air-speed vector, and the
plane's velocity <span>relative to the ground drops to 340 km/hr east</span>.
Can you explain this a bit more I don’t quite understand
Answer:
202.8m
Explanation:
Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.
First calculate the total time travelled by using the second equation of motion
h = Ut + 1/2gt^2
Let assume that u = 0
And h = 3.5
Substitute all the parameters into the formula
3.5 = 1/2 × 9.8 × t^2
3.5 = 4.9t^2
t^2 = 3.5/4.9
t^2 = 0.7
t = 0.845s
To know how far the cannonball travel, let's use the equation
S = UT + 1/2at^2
But acceleration a = 0
T = 2t
T = 1.69s
S = 120 × 1.69
S = 202.834 m
Therefore, the distance travelled by the cannon ball is approximately 202.8m.
It decomposes into CH3COO- and H+ when dissolved in water. The H+ ions react with the water molecules to generate H3O+, making the solution acidic. When NaOH is added to water, it separates into Na+ and OH-. The sodiums have little effect on the solution, but the hydroxyls make it more basic.
Answer: Take your pick
Explanation:
if they are all in parallel 1 /(1/100 + 1/300 + 1/50) = 30 Ω
if 50 is in parallel with 2 in series 1 / (1/(100 + 300) + 1/50) = 44.444...Ω
if 100 is in parallel with 2 in series 1 / (1/(50 + 300) + 1/100) = 77.777...Ω
if 300 is in parallel with 2 in series 1 / (1/(100 + 50) + 1/300) = 100 Ω
If 50 is in series with 2 in parallel 50 + 1/(1/100 + 1/300) = 125 Ω
If 100 is in series with 2 in parallel 100 + 1/(1/50 + 1/300) = 142.857...Ω
If 300 is in series with 2 in parallel 300 + 1/(1/50 + 1/100) = 333.333...Ω
If they are all in series 100 + 300 + 50 = 450 Ω
