It’s 49% of its original gig hope this helps!
Answer:
The y-component of the electric force on this charge is 
Explanation:
<u>Given:</u>
- Electric field in the region,

- Charge placed into the region,

where,
are the unit vectors along the positive x and y axes respectively.
The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

Thus, the y-component of the electric force on this charge is 
Answer: MOTION
Explanation:
motion is defined as the displacement of an object with respect to time relative to a stationary object (reference point). A good example of an object that can serve as a reference point includes: a tree or a building. The movement of a body at constant speed towards a particular direction at regular intervals of time can be determined and it's called uniform motion.
There are different types of motion, these includes: simple harmonic motion,
linear motion,
circular motion,
Brownian motion,
Rotatory motion
Few moons
I just took the test and got it right