A kite has diagonals 5.8 ft and 6ft. what is the area of the kite
2 answers:
The diagonals of a kite perpendicularly bisects each other dividing the kite in to four right angled triangles. The area of the kite is given by = pq/2, where p and q are the two diagonals of the kite Therefore, A = (5.8 × 6)/2 = 17.4 square feet
Answer:
17.4 square feet
Step-by-step explanation:
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Answer:
t≤ 9
Step-by-step explanation:
3.5+4t≤ 39.5
subtract 3.5 from each side
4t≤ 36
divide each side by 4
t≤ 9
I think the answer is b 0.2(20)
BPD = 1/2(BD + CA) BPD = 1/2(70 + 170) BPD = 1/2(240) BPD = 120 A full circle = 360 degrees BC + AD = 360 - 70 - 170 BC+ AD = 360 - 240 BC + AD = 120