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nika2105 [10]
3 years ago
11

I really need this answered fast.....The coordinates of the vertices of △JKL are J(−5, −1) , K(0, 1) , and L(2, −5) . Which stat

ement correctly describes whether △JKL is a right triangle? △JKL is not a right triangle because no two of its sides are perpendicular. △JKL is a right triangle because JK ¯ ¯ ¯ ¯ ¯ is perpendicular to KL ¯ ¯ ¯ ¯ ¯ . △JKL is a right triangle because JK ¯ ¯ ¯ ¯ ¯ is perpendicular to JL ¯ ¯ ¯ ¯ ¯ . △JKL is a right triangle because JL ¯ ¯ ¯ ¯ ¯ is perpendicular to KL ¯ ¯ ¯ ¯ ¯
Mathematics
2 answers:
dimulka [17.4K]3 years ago
5 0
<span>JKL is a right triangle because JK ¯ ¯ ¯ ¯ ¯ is perpendicular to KL</span>
grigory [225]3 years ago
3 0

Answer:

The answer was *△JKL is not a right triangle because no two of its sides are perpendicular.*

Step-by-step explanation:

Because, it's sides are not perpendicular to each other.

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\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

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\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

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\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

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