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Tatiana [17]
4 years ago
9

What’s 4,860 divided by 10 to the 2nd power?

Mathematics
2 answers:
Triss [41]4 years ago
6 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ 4,860 ÷ 10² = 48.6

Convert 10² into a whole number:

10 × 10 = 100

Divide:

4,860 ÷ 10 = 48.6

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

andriy [413]4 years ago
5 0

4860 divided by 10 is 486

486 to the second power is 236196.

When it is asking to the second power it is that number time its self that many times. So if I have 2 to the 4 power it is 2x2x2x2 so 2x2 is 8 and 8x8 is 16.

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Answer:

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The quality control manager can use a one-sample test to determine whether the mean life is 7,520 hours or not.

The hypothesis can be defined as follows:

<em>H₀</em>: The mean life of a large shipment of CFL bulbs is equal to 7,520 hours, i.e. <em>μ</em> = 7520.

<em>Hₐ</em>: The mean life of a large shipment of CFL bulbs is different from 7,520 hours, i.e. <em>μ</em> ≠ 7520.

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As the population standard deviation is provided, we will use a <em>z</em>-test for single mean.

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z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{7324-7520}{1200/\sqrt{64}}=-1.31

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If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the <em>p</em>-value for the two-tailed test as follows:

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The <em>p</em>-value of the test is 0.1902.

The <em>p</em>-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, it can be concluded that the mean life of a large shipment of CFL bulbs is equal to 7520 hours.

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