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sertanlavr [38]
4 years ago
6

How do altitude and temperature affect atmospheric pressure

Chemistry
1 answer:
sergij07 [2.7K]4 years ago
4 0
Pressure<span> with </span>Height<span>: </span>pressure<span> decreases with increasing </span>altitude<span>. The </span>pressure<span> at any level in the </span>atmosphere<span> may be interpreted as the total weight of the </span>air<span> above a unit area at any </span>elevation<span>. At higher elevations, there </span>are<span> fewer </span>air<span> molecules above a given surface than a similar surface at lower levels.</span>
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What is the frequency and energy per quantum (in Joules) of :
viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at 3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1} in vacuum.

f = \dfrac{c}{\lambda}

where

  • f is the frequency of the electromagnetic radiation,
  • c is the speed of light, and
  • \lambda is the wavelength of the radiation.

(a)

Convert all units to standard ones.

\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}.

The unit of f shall also be standard.

f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}.

For each particle,

E = h\cdot f,

where

  • E is the energy of the particle,
  • h is the planck's constant where h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}, and
  • f is the frequency of the particle.

E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}.

(b)

Try the steps in (a) for this beam of microwave with

  • \lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}.

Expect the following results:

  • f = 1.20\times 10^{10}\;\text{Hz}, and
  • E = 7.96\times 10^{-24}\;\text{J}.
4 0
3 years ago
In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay
nikdorinn [45]

Answer:

1984

Explanation:

Given the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the radioactive isotope

t= age of the wine

Ao= initial activity of the wine

A= activity of the at time = t

0.693/12.3 = 2.303/t log (5.5/0.688)

0.693/12.3 = 2.079/t

0.056 = 2.079/t

t= 2.079/0.056

t= 37 years

The wine was produced 37 years ago which means that it was produced in the year 1984

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3 years ago
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The bank will represent  evolutionary. hope that helped
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