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agasfer [191]
3 years ago
13

Determine if the numerical value describes a population parameter or a sample statistic. 74% of all instructors at your school t

each 2 or more classes.
Mathematics
1 answer:
notka56 [123]3 years ago
6 0

Answer:

Population parameter

Step-by-step explanation:

We are given the following in the question:

74% of all instructors at your school teach 2 or more classes.

Parameter and statistic:

  • Parameter is the value that describes a population.
  • Population is the collection of all the possible observations of an event.
  • Statistic is the quantitative value that describes a sample.
  • A sample is a part of a population and is always smaller than a population.

Population:

all instructors at your school

Parameter:

74% of all the instructors at your school teach 2 or more classes

Thus, 74% describes the population that takes two or more classes.

Hence, it is a population parameter.

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 surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft, can be solved by solving the area of each face of a cube. since the cube has 6 faces and all the faces are congruent because it all has the same edge.
so the formulaA = 6s^2where s is the edge lengthA = 6 ( 7.2^2)A = 311.04 sq ft.
8 0
3 years ago
Please answer 1-4 please
Nady [450]

Answer:

1. 1st Quadrant

2. 3rd Quadrant

3. 2nd Quadrant

4. 2nd Quadrant

5. 4rth Quadrant

6. 2nd Quadrant

7. No they do no correspond to the same point.

Step-by-step explanation:

1st Quadrant : ( positive , positive )

2nd Quadrant : ( negative , positive )

3rd Quadrant : ( negative , negative )

4th Quadrant : ( positive , negative )

3 0
3 years ago
Read 2 more answers
Parker Middle School's chior needs to raise $480 for an upcoming trip they will take. At their first fundraising project, they r
harkovskaia [24]

The money does the choir still need to raise is $180.

<u>Step-by-step explanation:</u>

The money needed to be raised by the choir for an upcoming trip = $480.

It is given that, the money needed was raised in two fundraising projects.

<u>During the first fundraising project :</u>

The choir raised 25% of the money needed for the trip.

⇒ 25% of 480

⇒ (25/100) × 480

⇒ (1/4) × 480

⇒ 120

Therefore, the first fundraising project raised $120.

<u>During the second fundraising project :</u>

The choir raised 3/8 of the money needed for the trip.

⇒ 3/8 of 480

⇒ (3/8) × 480

⇒ 3 × 60

⇒ 180

Therefore, the second fundraising project raised $180.

<u>To find the money does the choir still need to raise :</u>

You need to find the remaining amount from the 480 after raising money from the two fund raising projects.

For that, find out how much you raised from those fund raising projects and subtract it from the 480.

Money needed = Total money required for the trip - Raised money

⇒ 480 - (120+180)  

⇒ 480 - 300

⇒ 180 dollars.

The money does the choir still need to raise is $180.

6 0
3 years ago
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

3 0
3 years ago
PLEASE HELP!!!! Show steps and explain how to get the answer please <br><br> Solve 5x-16=4(x-8)-3x
Anvisha [2.4K]

5x-16 = 4(x-8)-3x

first expand what is in parenthesis

4(x-8) = 4x-32

 so now you have 5x-16 = 4x-32-3x

subtract 3x from 4x on the right side of equation 4x-3x = x

5x-16 = x -32

subtract 1x from each side to get

4x-16 = -32

add 16 to both sides to get 4x=-16

x = -16/4 = -4

x=-4

6 0
3 years ago
Read 2 more answers
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