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Finger [1]
3 years ago
6

Explain how changing the concentration of reactants can affect the rate of reaction.

Chemistry
1 answer:
Stells [14]3 years ago
3 0

Answer:

Increasing the concentration of a substance will increase the rate of reaction because in a conc substance the particles are more clustered together and this causes more effective collisions thus increasing the rate of reaction and when the substance isn't concentrated the particles aren't really close and this reduces the rate of reaction because alot of collisions can't be made compared to that of the concentrated substance

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PLEASE HELP WILL MARK AS BRAINEST!!!!!!!!!!!!
Elanso [62]

The answers to your question is B hope this helps.

5 0
2 years ago
The total pressure of a mixture of oxygen and hydrogen
Mandarinka [93]

Answer:

The composition of the original mixture in molepercent is 80% of H₂ and 20% of O₂.

Explanation:

We need to combine the ideal gas law (PV = nRT) and Dalton's law of partial pressure (Pt = Pa +Pb +Pc+...).

The total pressure of the mixture is Pt = P (H₂) + P (O₂)

The number of moles can be found by Pt = nt RT/V, in which nt = n (H₂) +n (O₂).

If Pt is 1 atm, nt is 1.0 mol.

Now we need to consider the chemical reaction below:

H₂ + 0.5O₂ → H₂O

This shows that for each mol of O₂ we need two mol of H₂.

We know that the remaining gas is pure hydrogen and that its pressure is 0.4atm. Since PV = nRT, by the end of the reaction, 0.4 mol of H₂ remains in the system.

This means that in the beginning we have n mol of H₂, and when x mol of H₂ reacts with 0,5x mol of O₂, 0.4 mol of H₂ reamains.

If we have 1 mol in the begining and 0.4 mol in the end, the total amount of gas that reacted (x + 0.5X) is equal to 0.6 mol

x + 0.5X = 0.6 mol ∴ x = 0.6 mol / 1.5 ∴ x = 0.4 mol

0.4 mol of H₂ reacted with 0.2 mol of O₂ and 0.4 mol of H₂ remained as excess.

Therefore, in the beginning we had 0.8 mol of H₂ and 0.2 mol of O₂. Thus the molepercent of the mixture is 80% of H₂ and 20% of O₂.

3 0
3 years ago
Which statement is true about real gases with the correct reason:
LenKa [72]

There are 2 possible answers here : b and d.

The Ideal Gas Equation is : <u>PV = nRT</u>

<u />

Here, when pressure is increased and temperature is lowered, the volume of the molecules will substantially decrease, which means it has deviated from ideal behavior.

4 0
2 years ago
Read 2 more answers
What is the molar mass of <br> C4H9, 114.17 g/mol
mihalych1998 [28]

Answer:

4 x 12 +9 x 1= 56

Explanation:

I do not know what the 114.17 g/mol comes from

6 0
3 years ago
Read 2 more answers
In the following reaction, how many moles of CO2 will form if 10 moles of C3H4 are reacted? How many moles of O2 will also be co
umka2103 [35]

Answer:

40 moles of O₂

30 moles of CO₂

Explanation:

Given parameters:

Number of moles of C₃H₄  = 10moles

Unknown:

Number of moles of CO₂ = ?

Solution:

The number of moles helps to understand and make quantitative measurements involving chemical reactions.

We start by solving this sort of problem by ensuring that the given equation is properly balanced;

        C₃H₄    +      4O₂    →     3CO₂     +      2H₂O

We can clearly see that all the atoms are conserved.

Now, we work from the known to unknown. We know the number of moles of  C₃H₄ to be 10moles;

             1 mole of  C₃H₄ reacted with 4 moles of O₂

              10 moles of C₃H₄ will react with 10 x 4 = 40moles of O₂

      1 mole of  C₃H₄ will produce 3 moles of CO₂

       10 moles of C₃H₄ will produce 10 x 3 = 30moles of CO₂

   

4 0
2 years ago
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