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Taya2010 [7]
2 years ago
5

A constant current of 0.350 A is passed through an electrolytic cell containing molten CrCl₂ for 21.7 h. What mass of Cr(s) is p

roduced? The molar mass of chromium is 52.0 g/mol. Provide your answer rounded to 3 significant digits.​
Chemistry
1 answer:
zhuklara [117]2 years ago
4 0

An electrochemical cell can generate or use electrical energy. The mass of solid chromium that will be deposited on the electrochemical plate is 7.17 gm.

<h3>What is current?</h3>

Current in an electrochemical cell is the ratio of the quantity of electricity in columns and time in seconds.

Given,

Current (I) = 0.350 A

Time = 21.7 hours

Molar mass of chromium = 52.0 g/mol

First time is converted into seconds:

1 hour = 3600 seconds

21.7 hours = 76020 seconds

The quantity of electricity flowing in the electrochemical solution is calculated as:

\begin{aligned} \rm Q & = \rm It\\\\& = 0.350 \times 76020 \\\\& = 26607\;\rm C \end{aligned}

Electricity required for depositing 1 mole or 52.0 g chromium is calculated as:

In electrochemical solution, chromium chloride is dissociated as:

\rm CrCl_{2} \rightarrow Cr^{2+} + 2 Cl^{-} \\\\\rm Cr^{2+} +2 e^{-} \rightarrow Cr

Two moles of electrons are needed to deposit 52.0 g of chromium.

If, 1 electron = 96500 C

Then, 2 electron = 193000 C

The mass of chromium deposited is calculated as:

193000 C = 52 g chromium

So, 26607 C = \dfrac{26607 \times 52}{193000} = 7.17 \;\rm gm

Therefore, 7.17 gm of chromium is produced.

Learn more about an electrochemical cell here:

brainly.com/question/20355190

#SPJ1

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Answer:

116.5 g of SO₂ are formed

Explanation:

The reaction is:

S₈(g) +  8O₂(g)  → 8SO₂ (g)

Let's identify the moles of sulfur vapor, by the Ideal Gases Law

We convert the 921.4°C to Absolute T° → 921.4°C + 273 = 1194.4 K

5.87 atm . 3.8L = n . 0.082 L.atm/mol.K . 1194.4K

(5.87 atm . 3.8L) / (0.082 L.atm/mol.K . 1194.4K) = n → 0.228 moles of S₈

Ratio is 1:8, 1 mol of sulfur vapor can produce 8 moles of dioxide

Then, 0.228 moles of S₈ must produce (0.228 . 8) /1 =  1.82 moles

We convert the moles to g → 1.82 moles . 64.06 g /1mol = 116.5 g

3 0
3 years ago
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Hydrogen and oxygen are elements.
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In a labratory activity the density of a sample of vanadium is determined to be 6.9g/cm^3 at room temperature. what is the perce
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Answer:

c : 13%

Explanation:

Data Give:

Experimental density of vanadium = 6.9 g/cm³

percent error = ?

Solution:

Formula used to calculate % error

  % error = [experimental value -accepted value/accepted value] x 100

The reported accepted density value for vanadium = 6.11 g/cm³

Put value in the above equation

                  % error = [ 6.9 - 6.11 / 6.11 ] x 100

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3 years ago
If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
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Answer:

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Explanation:

It is an example of acid-base neutralization reaction.

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Base           Acid                           Salt                                    

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