An electrochemical cell can generate or use electrical energy. The mass of solid chromium that will be deposited on the electrochemical plate is 7.17 gm.
<h3>What is current?</h3>Current in an electrochemical cell is the ratio of the quantity of electricity in columns and time in seconds.
Given,
Current (I) = 0.350 A
Time = 21.7 hours
Molar mass of chromium = 52.0 g/mol
First time is converted into seconds:
1 hour = 3600 seconds
21.7 hours = 76020 seconds
The quantity of electricity flowing in the electrochemical solution is calculated as:
Electricity required for depositing 1 mole or 52.0 g chromium is calculated as:
In electrochemical solution, chromium chloride is dissociated as:
Two moles of electrons are needed to deposit 52.0 g of chromium.
If, 1 electron = 96500 C
Then, 2 electron = 193000 C
The mass of chromium deposited is calculated as:
193000 C = 52 g chromium
So, 26607 C =
Therefore, 7.17 gm of chromium is produced.
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Answer:
The structure for the compound elucidated (4-Ethylbenzoic acid) is attached below.
Explanation:
Degree of Unsaturation = (where n = no of moles)
=
= 9 - 6+1 = 4
⇒ 2 ring. 3 double bonds.
From the 1H NMR data given (peaks labeled A-E)
A. 1.2 (3H, t) ⇒ -CH3
B. 2.6 (2H, q) ⇒ -C=C-H or Aromatic-CH3
C. 7.3 (2H, d) ⇒ Aro.-H
D. 8.0 (2H, d) ⇒ Aro.-H
E. 11.0 (1H, s) ⇒ -COOH
Answer:
a.
1. NO2(g): Reactant.
2. CO(g): Reactant.
3. NO3(g): Intermediate.
4. CO2(g): Product.
5. NO(g): Product.
b. See attached picture.
Explanation:
Hello,
a. In this case, given the reactions, we can identify each species as:
1. NO2(g): Reactant because it remains at the left side in the overall reaction.
2. CO(g): Reactant because it remains at the left side in the overall reaction.
3. NO3(g): Intermediate because it is a product in the step 1 and a reactant in step 2, for that reason it is not present in the overall reaction.
4. CO2(g): Product because it remains at the right side in the overall reaction.
5. NO(g): Product because it remains at the right side in the overall reaction.
b. In this case, given that the first step is slow and endothermic, it has a high activation energy and the products will have more energy than the reactants, for that reason the final energy is above the initial point. Moreover, since the second step is fast and exothermic, it has a low activation energy and the products will have less energy than the reactants, for that reason, the reaction coordinate diagram is shown on the attached file.
Regards.
