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elixir [45]
3 years ago
15

What is the molar mass of C4H9, 114.17 g/mol

Chemistry
2 answers:
mihalych1998 [28]3 years ago
6 0

Answer:

4 x 12 +9 x 1= 56

Explanation:

I do not know what the 114.17 g/mol comes from

mrs_skeptik [129]3 years ago
3 0

<u>Answer:</u> The molar mass of C_4H_9 is 57.134 g/mol

<u>Explanation:</u>

Molar mass is defined as the sum of the mass of all the atoms each multiplied its atomic masses that are present in the molecular formula of a compound. It is expressed in g/mol.

We are given:

A chemical compound having molecular formula C_4H_4

We know that:

Molar mass of carbon = 12.011 g/mol

Molar mass of hydrogen = 1.01 g/mol

Molar mass of C_4H_9=(4\times 12.011)+(9\times 1.01)=57.134g/mol

Hence, the molar mass of C_4H_9 is 57.134 g/mol

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kaheart [24]
CrP is Chromium Phosphide

SnI2 is Tin(II) Iodine

Sni4 is Tin

SnS is Tin(II) Sulfide

SnS2 is Tin Sulfide
8 0
3 years ago
Write the formula to iron (III) oxide and iron (III) carbonate
NemiM [27]

Answer:

iron (III) oxide =Fe2O3

iron(III) carbonate =Fe2(CO3)3

4 0
2 years ago
How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?
Delvig [45]

Hi there!

\large\boxed{3.203 *  10^{22} atoms}

We can use the following conversions to solve:

Total mass --> amount of mols --> amount of atoms (Avogadro's number)

Begin by calculating the amount of boron trifluoride in 3.61 grams:

3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃

Use avogadro's number to convert:

0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms

3 0
2 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
Convert 10 liter into m3.
stellarik [79]
0.01 cubic meters
Hope this helps
3 0
3 years ago
Read 2 more answers
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