It is the the ecrins of light
The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m
Explanation:
Let's solve this problem in parts
let's start by finding the intensity of the sound in each observer
observer A β = 59 db
β = 
where I₀ =
W / m²

=
W / m²
Similarly for Observer b 
now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed
P = I A
therefore for the two observers
the area of a sphere is

we substitute the above formula, we get
Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

after solving the above equation we get x = 28.64 m
This is the distance of observer A
similarly The distance from observer B is 35 - x
= 40 - 28.64
= 11.36m
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Answer:
The Required pressure for this situation is P= 735000Pa
Explanation:
In Determining the required pressure in this situation we use two equations
First one is
F = mg = (ρhA)g
And Second one is
P =
= (ρhAg)/A Where P is pressure
We get
P = ρhg
since g = 9.8 m/s and h is given that is 75m and ρ = 
so
P = (9.8 m/s)(
)(75) we get
P = 735000 Pa
Answer:

Explanation:
given,
magnetic field strength = 1.40 ✕ 10⁻³ T
frequency of oscillation = 60 Hz
diameter of RBC = 7.5 μm
EMF = ?





maximum emf that can generate around the perimeter of the cell 