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4 years ago

Hey can you plz help me

Physics

1 answer:

Georgia [21]4 years ago

7 0

Answer:

I can't do the sketch

the direction of elections would move though the wires opposite direction

the 3rd one I'm not sure

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NEED THE ANSWER PLZ<br><br>What are lanthanides?

geniusboy [140]

It is the the ecrins of light

5 0

3 years ago

We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3

GalinKa [24]

we would be at (4,0)

7 0

3 years ago

A stereo speaker is placed between two observers who are 40 m apart, along the line connecting them. if one observer records an

Nadya [2.5K]

The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

β = $10 log\frac{I_a}{I_o}$

where I₀ = $1 \times 10^{-12}$ W / m²

$I_a = I_b \times 10 ^{ \frac{\beta}{10} }$

$I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }$

$I_a$ = $2.51 \times 10 ^{-6}$ W / m²

Similarly for Observer b $I_b = 3.16 \times 10 ^ {-4}$

now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of a sphere is

$A= 4\pi \times r^2$

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

$I_a (35 -x) ^2 = I_b x^2$

after solving the above equation we get x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

To know more about intensity of sound with the given link

#SPJ4

6 0

1 year ago

A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp

Fantom [35]

Answer:

The Required pressure for this situation is P= 735000Pa

Explanation:

In Determining the required pressure in this situation we use two equations

First one is

F = mg = (ρhA)g

And Second one is

P = $F/A$ = (ρhAg)/A Where P is pressure

We get

P = ρhg

since g = 9.8 m/s and h is given that is 75m and ρ = $1000 kg/m^3$

P = (9.8 m/s)( $1000 kg/m^3$ )(75) we get

P = 735000 Pa

6 0

4 years ago

Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne

slega [8]

Answer:

$\epsilon = 2.96 \times 10^{-11} \ V$

Explanation:

given,

magnetic field strength = 1.40 ✕ 10⁻³ T

frequency of oscillation = 60 Hz

diameter of RBC = 7.5 μm

EMF = ?

$\epsilon = NBA\omega$

$\epsilon = NB(\pi\ r^2)\ (2\pi f)$

$\epsilon = NB(\pi\ (\dfrac{d}{2})^2)\ (2\pi f)$

$\epsilon = (1)\ 1.4 \times 10^{-3}(\pi\ (\dfrac{7.5 \times 10^{-6}}{2})^2)\ (2\pi\times 60)$

$\epsilon = 2.96 \times 10^{-11} \ V$

maximum emf that can generate around the perimeter of the cell $\epsilon = 2.96 \times 10^{-11} \ V$

5 0

3 years ago