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lbvjy [14]
3 years ago
7

Pls help me 10 points

Physics
2 answers:
serious [3.7K]3 years ago
4 0

d. Global winds

I hope it's help you...

Thanks♥♥

lapo4ka [179]3 years ago
3 0

Answer:

d is the right answer

it's was helpful to you

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What happens to your kinectic energy when your gravitational potential energy decreases?
leonid [27]

Answer:

As r decreases, we lose gravitational potential energy - in other words, U G U_G UG​U, start subscript, G, end subscript becomes more negative. Because energy is conserved, the velocity must increase, resulting in an increase in kinetic energy.

Explanation:

3 0
3 years ago
A 7-hp (shaft) pump is used to raise water to an elevation of 19 m. if the mechanical efficiency of the pump is 82 percent, dete
Hoochie [10]
Convert the units of power,W = 7 hp = 7 * 745.69 = 5219.83 WCalculate the power input to the pump using the efficiency of the pump equationn=Wpump/Wshaft
Substitute 0.82 for n and 5219.83 for Wshaft0.82=Wpump/5219.83   Wpump=0.82*5219.83=4280.26 WCalculate the mass flow ratein=Wpump/(gz_2 )Where g is the acceleration due to gravity, and z_2 is the elevation of water. Substitute 4280.26 for Wpump, 9.81 m/s^2 for g, and 19m for z_2in = 4280.26 / 9.81 * 19 = 22.9640 m^3/sCalculate the volume flow rate of waterV=m/ρWhere ρ is the density of water. Substitute 22.9640  m^3/s for in and 1000  m^3/kg for ρ, we get V = 22.9640 / 1000 = 0.0230 kg/sTherefore, the volume flow rate of water is 0.0230 kg/s
7 0
3 years ago
A viscous liquid is sheared between two parallel disks of radius �, one of which rotates with angular speed Ω, while the other i
Alexus [3.1K]

Answer:

Upper disk rotates at a constant angular velocity. The velocity at any height from stationery disk, say at x metres

U_o=v(\frac {x}{h}) where v is tangential velocity at radius r from the centre of disk

U_o=r\omega (\frac {x}{h})

The radial component of velocity is given as

U_r=0

The z component of velocity is also given as  

W=0

Total velocity, v= r\omega (\frac {x}{h})\hat e_{o}

5 0
3 years ago
Please answer ASAP!!!!
RoseWind [281]
The answer is Ultraviolet
6 0
3 years ago
An old-fashioned LP record rotates at 33 1/3 RPM
Ksenya-84 [330]

Answer:

Part a) \frac{5}{9}\ \frac{rev}{sec}

Part b) \frac{9}{5}\ \frac{sec}{rev}

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

so

33\frac{1}{3}\ \frac{rev}{min}

Convert mixed number to an improper fraction

33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}

Remember that

1\ min=60\ sec

Convert rev/min to rev/sec

\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}

Simplify

\frac{5}{9}\ \frac{rev}{sec}

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

\frac{9}{5}\ \frac{sec}{rev}

4 0
3 years ago
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