Answer:
#_time = 7.5 10⁴ s
Explanation:
In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.
t =
where t_p is the person's own time in an immobile reference frame,

let's calculate
we assume that the speed of the space station is constant
t_ = 0.99998666657 s
therefore the time change is
Δt = t - t_p
Δt = 1 - 0.9998666657
Δt = 1.3333 10⁻⁵ s
this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s
#_time = 1 / Δt
#_time =
#_time = 7.5 10⁴ s
Answer:
Proof in explanataion
Explanation:
The basic dimensions are as follows:
MASS = M
LENGTH = L
TIME = T
i)
Given equation is:

where,
H = height (meters)
u = speed (m/s)
g = acceleration due to gravity (m/s²)
Sin Ф = constant (no unit)
So there dimensions will be:
H = [L]
u = [LT⁻¹]
g = [LT⁻²]
Sin Ф = no dimension
Therefore,
![[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]](https://tex.z-dn.net/?f=%5BL%5D%20%3D%20%5Cfrac%7B%5BLT%5E%7B-1%7D%5D%5E2%7D%7B%5BLT%5E%7B-2%7D%5D%7D%5C%5C%5C%5C%5C%20%5BL%5D%20%3D%20%5BL%5E%7B%282-1%29%7DT%5E%7B%28-2%2B2%29%7D%5D)
<u>[L] = [L]</u>
Hence, the equation is proven to be homogenous.
ii)

where,
F = Force = Newton = kg.m/s² = [MLT⁻²]
G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²
G = [M⁻¹L³T⁻²]
m₁ = m₂ = mass = kg = [M]
r = distance = m = [L]
Therefore,
![[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\](https://tex.z-dn.net/?f=%5BMLT%5E%7B-2%7D%5D%20%3D%20%5Cfrac%7B%5BM%5E%7B-1%7DL%5E%7B3%7DT%5E%7B-2%7D%5D%5BM%5D%5BM%5D%7D%7B%5BL%5D%5E2%7D%5C%5C%5C%5C%5C%20%5BMLT%5E%7B-2%7D%5D%20%3D%20%5BM%5E%7B%28-1%2B1%2B1%29%7DL%5E%7B%283-2%29%7DT%5E%7B-2%7D%5D%5C%5C%5C%5C)
<u>[MLT⁻²] = [MLT⁻²]</u>
Hence, the equation is proven to be homogenous.
The answer is positive thoughts