Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
9×18 rectangle plus a (18-6-6)×4 right triangle
Area = 9×18 + (1/2)×6×4 = 174
Answer: 174 sq ft
Answer:
Step-by-step explanation:
Given
Change: -4, 7, -7 and 0
Required
Compare them
From the list of given options, we can observe that the inequality < is used in all options.
This implies that we arrange from least to highest
The least is -7
Then, -4
Then 0
And lastly, 7
So, we have:
I'm ASSUMING that we're talking about Three Ordered Ordered Pair Solutions.
If so, the answer is (0,−1),(1,2),(2,5).
