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erastovalidia [21]
3 years ago
10

Which two formulas contain 4 atoms of hydrogen

Chemistry
2 answers:
professor190 [17]3 years ago
6 0

Methane CH4 1 carbon atom : 4 hydrogen atoms

Sulfuric acid H2SO4 2 hydrogen atoms : 1 sulfur atom: 4 oxygen atoms

salantis [7]3 years ago
3 0

Methane CH4 1 carbon atom : 4 hydrogen atoms

Sulfuric acid H2SO4 2 hydrogen atoms : 1 sulfur atom: 4 oxygen atoms

HOPE THIS HELPED!! XD

Can I have brain? please

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What do nucleic acids and phospholipids have in common?
erastova [34]

They are both important cell signaling molecules and both of them contain phosphate groups.

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3 years ago
What is the formula for a hydrate that contains 5.99 g CuSO4 and 5.4 g H2O?
adoni [48]

A hydrate is a chemical that has water molecules loosely bonded to it. The water molecules are not ... You will be using the hydrate CuSO4 . ?H2O. Sample Calculation-. An empty crucible has a mass of 12.770 grams.

8 0
3 years ago
Why are significant figures rules for calculations more important in science than in math class?
inysia [295]

Answer:

The importance of significant figures

As stated before, it is important within the science fields that you are not more precise or accurate than the least accurate or precise number. In science, it is generally agreed upon that the last number digit in any figure is filled with uncertainty.

Explanation:

4 0
3 years ago
An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C
ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0
3 years ago
Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.1
tekilochka [14]

Answer:

3.26 % of vinegar is acetic acid

Explanation:

Step 1: Data given

Mass of the sample = 5.54 grams

Volume of NaOH = 30.10 mL

Molarity of NaOH = 0.100M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles NaOH

Moles NaOH = volume * molarity

Moles NaOH = 0.03010 L * 0.100M

Moles NaOH = 0.00301 moles NaOH

Step 4: Calculate moles CH3COOH

For 1 mol NaOH we need 1 mol CH3COOH

For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH

Step 5: Calculate mass CH3COOH

Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

Mass CH3COOH = 0.00301 moles * 60.05 g/mol

Mass CH3COOH = 0.1808 grams

Step 6: Calculate percent by weight of acetic acid

Mass % = ( 0.1808 / 5.54 ) *100%

Mass % = 3.26 %

3.26 % of vinegar is acetic acid

7 0
3 years ago
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