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marusya05 [52]
3 years ago
7

Please help I will mark your answer as brainliest!!!!

Chemistry
1 answer:
nydimaria [60]3 years ago
6 0

In the structure, we essentially have a Carbon with 3 methyl groups and a hydrogen attached to it

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How many grams of Zn could be extracted from 300. g of ZnS
BabaBlast [244]
150grams of zinc can be extracted
7 0
3 years ago
A chemist adds of a M calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist h
Levart [38]

Answer:

1.23 g

Explanation:

<em>A chemist adds 1.55 L of a 0.00582 M calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask.</em>

Step 1: Given data

  • Volume of the solution (V): 1.55 L
  • Molar concentration of the solution (C): 0.00582 M (0.00582 mol/L)

Step 2: Calculate the moles (n) of calcium sulfate added

We will use the following expression.

n = C × V

n = 0.00582 mol/L × 1.55 L

n = 0.00902 mol

Step 3: Calculate the mass corresponding to 0.00902 moles of calcium sulfate

The molar mass of calcium sulfate is 136.14 g/mol.

0.00902 mol × 136.14 g/mol = 1.23 g

6 0
3 years ago
Yogurt has an approximate pH of 5 and vinegar has an approximate pH of 3. How many times more acidic is vinegar compared to yogu
schepotkina [342]

Answer:

The vinegar is highly acidic by 100 times than yogurt.

Explanation:

∵ pH = -log[H⁺]

  • The concentration of H⁺ in yogurt:

∵ pH = -log[H⁺]

∴ 5 =  -log[H⁺]

∴  [H⁺] = 1.0 x 10⁻⁵ M.

  • The concentration of H⁺ in vinegar:

∵ pH = -log[H⁺]

∴ 3 =  -log[H⁺]

∴  [H⁺] = 1.0 x 10⁻³ M.

the ratio of H⁺ in vinegar to that in yogurt = 1.0 x 10⁻³ M / 1.0 x 10⁻⁵ M = 100.0.

<em>∴ The vinegar is highly acidic by 100 times than yogurt.</em>

<em></em>

8 0
3 years ago
Nucleotides consist offa phosphate group, a nitrogenous base, and a
Mkey [24]

Answer:

5-Carbon sugar

Explanation:

A nucleotide is made up of 3 things: a phosphate group, a 5-carbon sugar, and a nitrogenous base.

4 0
3 years ago
500 mL of a solution contains 1000 mg of CaCl2. Molecular weight of CaCl2 is 110 g/mol. Specific gravity of the solution is 0. C
dangina [55]

Answer:

a) 0,2% w/v

b) r=500

c) 0,0182 M

d) 0,0145 m

e) 0,0137 equivalents

Explanation:

a) % w/v means mass of solute in grams per 100 mililiter of solution. Thus:

%w/v= \frac{1,000 g CaCl2}{500mL}×100 = 0,2%w/v

b) Ratio strength is a way to express concentration.  For w/v is in 1g of solute <em>r</em> mililiters of solution have. Thus, r = 500 because we have in the first 1 g of CaCl₂ in 500 mL of solution.

c) Molarity is moles of solute per liter of solution, thus:

1,000 g of CaCl₂ × \frac{1mol}{110g} = 9,09×10⁻³ moles of CaCl₂

500 mL of solution  × \frac{1L}{1000mL} = 0,500 L of solution

M = \frac{9,09x10^{-3} moles }{0,500 L} = 0,0182 M

d) Molality is moles of solute per kg of solution.

Specific gravity is the ratio between density of the solution and density of a reference substance (Usually water). With a specific gravity of 0,8:

kg of solution = 0,500 L of solution × \frac{0,8 kg}{1L} =<em> </em><em>0,625 kg of solution</em>

m = \frac{9,09x10^{-3}moles }{0,625 kg} = 0,0145 m

e)  In a salt, equivalents are the number of moles ables to replace one mole of charge. In CaCl₂ is ¹/₂ because with  ¹/₂ moles of CaCl₂ it is possible to replace 1 mole of charges. Thus, in 1,5 L there are:

1,5 L ×\frac{0,0182 CaCl2 moles}{1L} × \frac{1equivalent}{2 moles} = 0,0137 equivalents

I hope it helps!

7 0
4 years ago
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