Here we have to calculate the amount of
ion present in the sample.
In the sample solution 0.122g of
ion is present.
The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-
K₂SO₄ = 2K⁺ + 
(Na)₂SO₄=2Na⁺ + 
Thus, BaCl₂+
= BaSO₄↓ + 2Cl⁻ .
(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of
ion is precipitated in this reaction.
The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.
Now the molecular weight of BaSO₄ is 233.3 g/mol.
We know the molecular weight of sulfate ion (
) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of
ion is present.
Or. we may write in 233.3 g of BaSO₄ 96.06 g of
ion is present. So in 1 g of BaSO₄
g of
ion is present.
Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of
ion is present.
Answer: Skier 1 will have more potential energy because he is higher than skier 2
Explanation: Gravitational potential energy is the energy possessed by a body by virtue of its position or height.
P.E=
m= mass of the body
g= acceleration due to gravity
h= height of body
Thus if the masses of two bodies are same, the one with greater height possess greater potential energy.
Answer:
6l
Explanation: convert temperature to kelvin by adding 273 and then input the values into the formula with the given constant
2*v=0.5*0.8206*288 then divide both sides by 2 and get the amount in litres which is 6
Answer:
Neutral
Explanation:
They have the same # of protons and electrons