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erastova [34]
3 years ago
15

Write formulas for binary ionic compounds formed from each of the following pairs of elements

Chemistry
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

Binary compounds of potassium and sulfur:

K₂S

Binary compounds of silver chlorine:

AgCl

Binary compounds of calcium and oxygen:

CaO

Binary compounds of aluminium and iodine:

AlI₃

Binary compounds of barium and nitrogen:

Ba₃ N₂

Binary compounds of sodium and selenium:

Na₂Se

Explanation:

Binary compounds:

The compounds which are made up of the atoms of only two elements are called binary compounds.

For example:

The following compounds are binary:

HCl

H₂O

NH₃

HCl is binary because it is composed of only hydrogen and chlorine. Ammonia is also binary compound because it is made up of only two elements nitrogen and hydrogen.

water is also binary because it is also made up of only two elements hydrogen and oxygen.

Binary compounds of potassium and sulfur:

K₂S

The oxidation state of potassium is +1 and sulfur is -2 so two atoms of potassium will combine with one atom of sulfur.

Binary compounds of silver chlorine:

AgCl

The oxidation state of silver is +1 and chlorine is -1. Both combine to form silver chloride.

Binary compounds of calcium and oxygen:

CaO

calcium oxide is formed by calcium and oxygen. The oxidation state of calcium is +2 and oxygen is -2.

Binary compounds of aluminium and iodine:

AlI₃

The oxidation state of aluminium is +3 and iodine is -1 so three atoms of iodine will combine with one atom of aluminium.

Binary compounds of barium and nitrogen:

Ba₃ N₂

Barium nitride is formed by barium and nitrogen. The oxidation state of nitrogen is -3 and barium is +2.

Binary compounds of sodium and selenium:

Na₂Se

The oxidation state of selenium is -2 ans sodium is +1 so two atoms of sodium will combine with one atom of selenium.

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The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0
4 years ago
How many milliliters of a 1.25 molar hydrochloric acid solution would be needed to react completely with 60 grams of calcium
Fittoniya [83]
2HCl + Ca = CaCl₂ + H₂

n(HCl)=cv
n(Ca)=m(Ca)/M(Ca)
n(HCl)=2n(Ca)

cv=2m(Ca)/M(Ca)

v=2m(Ca)/{cM(Ca)}

v=2*60/{1.25*40}=2.4 L


7 0
3 years ago
Ammonium chloride, ammonium sulfate and ammonium nitrate are used in fertilisers.
Hoochie [10]

Answer:

1.0625 g

Explanation:

Number of moles in 5g of NH4NO3 = 5.0g/80g/mol = 0.0625 moles

Again the balanced reaction equation is;

NH3 + HNO3 → NH4NO3

So,

1 mole of NH3 yields 1 mole of NH4NO3

x moles of NH3 yields 0.0625 moles of NH4NO3

x = 0.0625 moles of NH3

Mass of NH3 = number of moles * molar mass

Mass of NH3 = 0.0625 moles * 17g/mol

Mass of NH3 = 1.0625 g

7 0
3 years ago
explain what happens if high pressure is implemented on the equilibrium reaction . State your observations for both rate of reac
amm1812
The equilibrium position will shift in order to counterbalance the change. That means the equilibrium position will shift, lowering the pressure once more.... When the pressure on a gas reaction is increased, the equilibrium moves to the side with fewer molecules.
8 0
2 years ago
It’s about the periodic table of elements
Pie
Yes what the other person said can I plz get an thanks
3 0
3 years ago
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