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4 years ago

How does the use of hydroelectric energy compare to the use of coal?

1 answer:

4 0

<span>Hydroelectric energy uses the movement of water to spin a turbine and produce electricity. Coal is a fossil fuel that is burned as an energy source, which results in emissions such as carbon dioxide, nitrogen, and sulfur. Coal use is associated with waste products both from the mining process to acquire the coal and also from the actual use of coal itself. Hydroelectric energy does not involve waste, but does pose potential problems to waterways. Coal use is more common than the use of hydroelectric energy.</span>

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What is a control?

White raven [17]

Answer:

a is the answer

please mark it brainliest

6 0

3 years ago

Read 2 more answers

Someone help please :)

zlopas [31]

6.79 x 10⁶

<h3>Further explanation </h3>

Scientific Notation consists of 2 parts

1. the first part: the first digit followed by the decimal point

2. The second part: the power of 10 (the exponents).which shows the number of digits after the decimal point

To add/subtract, the exponents must be the same and then add/subtract the coefficient

convert the largest exponent

$\tt 7.2\times 10^6\rightarrow 72\times 10^5$

subtract the coefficients

$\tt =(72-4.1)\times 10^5\\\\=67.9\times 10^5\rightarrow 6.79\times 10^6$

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3 years ago

The isotope sodium-20 has how many protons?

Anna007 [38]

Answer:11

Explanation:

4 0

3 years ago

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Calculate your experimentally determined percent mass of water in Manganese(II) sulfate monohydrate. Report your result to 2 or

antoniya [11.8K]

Answer:

10.6%

Explanation:

The determined percent mass of water can be calculated from the formula of the hydrate by

dividing the mass of water in one mole of the hydrate by the molar mass of the hydrate and

multiplying this fraction by 100.

Manganese(ii) sulphate monohydrate is MnSO4 . H2O

1. Calculate the formula mass. When determining the formula mass for a hydrate, the waters of

hydration must be included.

1 Manganes 52.94 g = 63.55 g

1 Sulphur 32.07 g =

32.07 g 2 Hydrogen is = 2.02 g

4 Oygen =

64.00 g 1 Oxygen 16.00 = 16.00 g

151.01 g/mol 18.02 g/mol

Formula Mass = 151.01 + (18.02) = 169.03 g/mol

2. Divide the mass of water in one mole of the hydrate by the molar mass of the hydrate and

multiply this fraction by 100.

Percent hydration = (18.02 g /169.03 g) x (100) = 10.6%

The final result is 10.6% after the two steps calculations

4 0

3 years ago

How many ml of 0. 10 m naoh should the student add to 20 ml of 0. 10 m hf or if she wished to prepare a buffer with a ph of 3. 5

Lemur [1.5K]

The required volume of 0.10M NaOH solution that student will add is 20 mL.

<h3>How do we calculate the volume?</h3>

Volume of any solution which is required to prepare buffer will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ are the molarity and volume of NaOH solution.
M₂ & V₂ are the molarity and volume of HF solution.

On putting values, we get

V₁ = (0.1)(20) / (0.1) = 20mL

Hence required volume of NaOH solution is 20mL.

To know more about molarity & volume, visit the below link:

brainly.com/question/24305514

#SPJ4

3 0

2 years ago