Question

How many moles of MgS2O3 are in 223 g of the compound

Answer 1

Moles of MgS2O3 = 223/molar mass of MgS2O3
    
                              =   223/136.42 
                              =     1.634 moles.

Hope this helps!

Answer 2

Answer: 1.63 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=$

Given mass = 223 g

Molar mass = 136.4

$\text{Number of moles}=\frac{223g}{136.4g/mol}=1.63moles$

Thus there are 1.63 moles in 223 g of the compound.