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nadezda [96]
3 years ago
7

How many moles of MgS2O3 are in 223 g of the compound

Chemistry
2 answers:
Alexxandr [17]3 years ago
6 0
Moles of MgS2O3 = 223/molar mass of MgS2O3
    
                              =   223/136.42 
                              =     1.634 moles.

Hope this helps!
Karolina [17]3 years ago
6 0

Answer: 1.63 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=

Given mass = 223 g

Molar mass = 136.4

\text{Number of moles}=\frac{223g}{136.4g/mol}=1.63moles

Thus there are 1.63 moles in 223 g of the compound.

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<h3>Further explanation</h3>

Given

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Answer:

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