Given: 8CO + 17H2 → C8H18 + 8H2O In this chemical reaction, how many grams of H2 will react completely with 6.50 moles of CO? Ex
2 answers:
Answer:- 27.6 grams of hydrogen are required.
Solution:- The given balanced equation is:
From balanced equation, there is 8:17 mol ratio between CO and means 17 moles of hydrogen are required to react completely with 8 moles of CO.
Let's calculate the number of moles of hydrogen required to react completely with 6.50 moles of CO and convert to grams on multiplying by molar mass of hydrogen as:
=
So, 27.6 grams of hydrogen are required to react completely with 6.50 moles of CO.
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Answer:
1.33 × 10²⁴ molecules CO₂
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Reading a Periodic Table
- Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
97.3 g CO₂
<u>Step 2: Define conversions</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
= 1.33138 × 10²⁴ molecules CO₂
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂