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trasher [3.6K]
2 years ago
11

Explain why molten sodium chloride conducts electricity,but solid sodium chloride does not​

Chemistry
1 answer:
KatRina [158]2 years ago
6 0

Answer:

because molten sodium gives electricity too choloride

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Given the atomic mass of select elements, calculate the molar mass of each salt.
arlik [135]

Answer:

See explanation

Explanation:

Molar mass is obtained as the sum of relative atomic masses as follow;

For CaBr = 40.08 + 79.90 = 119.98 g/mol

For BeBr =  9.012 + 79.90 = 88.912 g/mol

For CdBr2 = 112.41 + 2(79.90) = 272.21 g/mol

For CuBr2 = 63.55 + 2(79.90) = 223.35 g/mol

3 0
3 years ago
Sugar dissolving in tea is it chemical or physical change?​
coldgirl [10]

Answer:

it is a physical change because when you heat up again a solution of sugar and tea you gonna obtain again sugar

5 0
3 years ago
Choose the formula for calculating percent composition.
kondor19780726 [428]

Answer:

The equation for percent composition is (mass of element/molecular mass) x 100.

please mark me as a brainlist

6 0
3 years ago
8. which change in state is associated with the heat of vaporization,
rewona [7]
The answer is 2, liquid to vapor because vaporization is the process of liquids to vapors.
8 0
3 years ago
The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

7 0
3 years ago
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