Answer:
1)
% or 20%
Step-by-step explanation:
Given that:
An experiment which is carried out by flipping a coin and rolling six sided die.
The outcomes can be:
{H1, H2, H3, H5, H6, T1, T1, T2, T3, T5}
As per question statement:
Number of outcomes having tails and an odd number greater than one is 2 (i.e. T3 and T5)
Total number of outcomes here is 10.
Therefore, to find the percentage, we use the following formula:
![\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times 100](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BNumber%20of%20favorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20number%20of%20outcomes%7D%7D%5Ctimes%20100)
![\Rightarrow \dfrac{2}{10}\times 100 = 20\%](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B2%7D%7B10%7D%5Ctimes%20100%20%3D%2020%5C%25)
As per question statement, the answer is 20%.
If we consider all the outcomes, i.e.
{H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}
Total number of outcomes = 12
The percentage will come out be :
![\Rightarrow \dfrac{2}{12}\times 100 = 16\frac{2}{3}\%](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B2%7D%7B12%7D%5Ctimes%20100%20%3D%2016%5Cfrac%7B2%7D%7B3%7D%5C%25)