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grandymaker [24]
3 years ago
15

11 swimming pool water can be kept free of harmful bacteria by adding aqueous sodium chlorate(i),naocl. this reacts with water t

o produce hocl molecules which kill bacteria.ocl–(aq) h2o(reversible) oh–(aq) hocl (aq)in bright sunshine, the ocl– ion is broken down by ultra-violet lightocl–(aq) uv light → cl–(aq) ½o2(g)which method would maintain the highest concentration of hocl (aq)?a acidify the pool waterb add a solution of chloride ionsc add a solution of hydroxide ionsd bubble air through the water
Chemistry
1 answer:
antoniya [11.8K]3 years ago
4 0
The answer is chlorine
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How many moles of SnCl2 will be produced if 85.3 g of FeCl3 is reacted with an excess of Sn for the following reaction:2 FeCl3(s
Ronch [10]

Answer:

The answer to your question is 0.79 moles of SnCl₂  

Explanation:

Data

moles of SnCl₂ = ?

mass of FeCl₃ = 85.3 g

excess Sn

Balanced chemical reaction

                 2 FeCl₃  +  3 Sn  ⇒   3 SnCl₂  +  2 Fe

Process

1.- Convert the mass of FeCl₃ to moles

Molar mass of FeCl₃ = 56 + (35.5 x 3)

                                  = 56 + 106.5

                                  = 162.5 g

Use proportions to find the moles of FeCl₃

                       162.5 g -------------------- 1 mol

                         85.3 g -------------------  x

                         x = (85.3 x 1) / 162.5

                         x = 0.525 moles

2.- Find the number of moles SnCl₂

                     2 moles of FeCl₃ ----------------- 3 moles of SnCl₂

                     0.525 moles        ----------------- x

                     x = (0.525 x 3) / 2

                    x = 0.79 moles of SnCl₂                  

4 0
4 years ago
1.2 g of sucrose is added to water with the final volume of 75 ml. What is the concentration of sucrose in %w/v?
Firlakuza [10]

Answer:

16 g/L

Explanation:

Given that:-

Mass of sucrose added = 1.2 g

Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )

%w/v is defined as the mass of the solution in 1 L of the solution.

So,

\%\ w/v=\frac{Mass_{solute}}{Volume_{Solution}}

\%\ w/v=\frac{1.2\ g}{0.075\ L}=16\ g/L

8 0
3 years ago
Is rust a pure substance or a mixture? <3
Naddik [55]
Iron is a pure substance
6 0
3 years ago
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A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
3 years ago
A molecular compound is?
Nezavi [6.7K]
Composed of molecules formed by atoms of two or more different elements.
3 0
4 years ago
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