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VikaD [51]
2 years ago
7

Which wavelength bands are just outside the visible range?

Chemistry
1 answer:
Norma-Jean [14]2 years ago
7 0

Answer: The ultraviolet or UV portion

Explanation:

The term comes from the fact that this type of radiation is slightly beyond the violet region of visible wavelengths

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What atom does not contain neutron​
weqwewe [10]

Answer:

There is only one stable atom that does not have neutrons. It is an isotope of the element hydrogen called protium. Protium, which contains a single proton and a single electron, is the simplest atom. All other stable atoms contain some number of neutrons. hope this helps you :)

4 0
3 years ago
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A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas?
prisoha [69]
We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure
V = volume
n = number of moles
R = gas constant, 0.08206 Latm/Kmol
T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT
T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm)(10.0 L)/(3.00 mol)(0.08206 Latm/Kmol)
T = 183 K

The temperature of the gas is 183 K.
3 0
3 years ago
Once the energy gets transferred to heat energy, is it reversible or irreversible?
denis-greek [22]
I believe the answer is reversible
7 0
4 years ago
Hat mass of ethane, c2h6, contains the same number of molecules as 3.00 g of trichlorofluoromethane, ccl3f?
Temka [501]

1. Calculate the molar masses of each compound:

C_2H_6 = 12\cdot 2 + 1\cdot 6 = 30\ g/mol

CCl_3F = 12\cdot 1 + 35.5\cdot 3 + 19\cdot 1 = 137.5\ g/mol

2. Both masses are referred to one mole of the substances. We can do a ratio between them and the 3 g of CCl_3F:

\frac{30\ g\ C_2H_6}{137.5\ g\ CCl_3F} = \frac{x}{3\ g\ CCl_3F}\ \to\ x = \bf 0.654\ g\ C_2H_6

5 0
3 years ago
Read 2 more answers
Calculate the number of moles of a gas if it occupies a volume of 4dm at 10atm and _200°c.
Rina8888 [55]
 The number  of moles of a gas if it occupy a volume of 4dm  at 10 atm and - 200 c   is 6.67  moles

  calculation
by use of ideal gas equation
that is PV =nRT
where  P(pressure) =  10 atm
           V( volume) =  4dm^3 = 4L
            n(number of moles) =?
             R(gas constant) = 0.0821 L.atm/mol.K
              T = -200  +273 =  73 K

make n the  formula  of  the subject  n = PV/RT

n is therefore =  (10 atm x 4l)/(0.0821 L.atm/mol.K  x 73 K)  =  6.67 moles
5 0
3 years ago
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