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ANEK [815]
2 years ago
9

As we move across the periodic table of elements, certain trends are evident. The placement of individual elements in the period

ic table allows us to predict many characteristics of elements such as state of matter at room temperature, reactivity, and valence electrons just to name a few. Let's compare the elements in Group #1 and Group #17. Identify the differences in the two families based on their locations in the periodic table. Choose ALL that apply
Question 20 options:

Group #1 elements are metals and Group #17 elements are nonmetals.


Group #1 elements form negative ions while Group #17 form positive ions.


Group #1 elements are reactive while Group #17 elements are non-reactive.


When forming compounds, Group #1 elements lose electrons and Group #17 elements gain electrons.
Chemistry
1 answer:
Soloha48 [4]2 years ago
4 0

Answer:

A and E

Explanation:

A and E are the answers! usa test prep told me.    :L

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Which solution contains the smallest number of moles of sucrose (c12h22o11, molar mass = 342.30 g/mol)? 2,000 ml of a 5.0 × 10–5
Iteru [2.4K]

> 2,000 mL of a 5.0 × 10–5% (w/v) sucrose solution 

5.0 × 10–3 g/mL * 2000 mL * (1 mol / 342.30 g) = 0.0292 mol

<span>
> 2,000 mL of a 5.0 ppm sucrose solution</span>

5 grams / 1000000 mL * 2000 mL* (1 mol / 342.30 g) = 0.0000292 mol

 <span>
> 20 mL of a 5.0 M sucrose solution </span>

5.0 M * 0.020 L = 0.1 mol

 

 

Answer:

<span>2,000 mL of a 5.0 ppm sucrose solution</span>

5 0
3 years ago
A vessel contains a mixture of gases. The mass of each gas used to make the mixture is known. Which of the following information
faltersainse [42]

Answer: The molar mass of each gas

Explanation:

Mole fraction is the ratio of moles of that component to the total moles of solution. Moles of solute is the ratio of given mass to the molar mass.

\text{Mole fraction of solute}=\frac{\text{Moles of solute}}{\text{Total Moles}}

Suppose if there are three gases A, B and C.

a) \text{Mole fraction of A}=\frac{\text{Moles of A}}{\text{ Moles of (A+B+C)}}

b) \text{Mole fraction of B}=\frac{\text{Moles of B}}{\text{ Moles of (A+B+C)}}

c) \text{Mole fraction of C}=\frac{\text{Moles of C}}{\text{ Moles of (A+B+C)}}

moles of solute =\frac{\text {given mass}}{\text {Molar mass}}

Thus if mass of each gas is known , we must know the molar mass of each gas to know the moles of each gas.

8 0
3 years ago
Please help me #6!!!!!!!!
Vesnalui [34]
I believe that the answer is 12 because there is already 3 O molecules and since its in parentheses with 3 outside it that means that there are 3 of those CO molecules meaning that for every 1 CO there will be 3 O’s so 3, four times Is 12
3 0
3 years ago
Which carbon atom(s) of pyruvate is(are) first converted to carbon dioxide by pyruvate dehydrogenase complex?
lilavasa [31]

The carbon atom(s) of pyruvate is(are) first converted to carbon dioxide by pyruvate dehydrogenase complex is the second number of carbon of pyruvate goes to oxidation and convert it to CO2 in Krebs cycle.

<h3>what is Krebs cycle ?</h3>

Krebs cycle is also known as citric acid cycle it is the conversion of sugar to the direct energy in the form of ATP which further goes to mitochondria as it is the power house of the human cell.

Pyruvate molecule release second number carbon from the chain and undergoes oxidation to form the CO2.

Therefore, second number carbon atom will converts to carbon dioxide.

Learn more about Krebs cycle , here:

brainly.com/question/14241294

#SPJ4

7 0
1 year ago
3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and t
DanielleElmas [232]

Answer:

4.67 kg

Explanation:

Given data

  • Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm
  • Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.

V = 75.0 cm \times  55.0 cm \times 0.10 cm = 413 cm^{3}

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.

\rho = \frac{m}{V} \\m = \rho \times V = \frac{11.3g}{cm^{3} }  \times 413cm^{3} = 4.67 \times 10^{3} g = 4.67 kg

6 0
2 years ago
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