Answer:
c(Al³⁺) = 0.52 mol·L⁻¹; c(SO₄²⁻) = 0.84 mol·L⁻¹
Explanation:
One mole of aluminium sulfate produces 2 mol of aluminium ions and 3 mol of sulfate ions.
If we apply the same proportionality, 0.26 mol of Al₂(SO₄)₃ produces 0.52 mol of Al³⁺ions and 0.84 mol of SO₄²⁻ ions.
Al₂(SO₄)₃(aq) ⟶ 2Al³⁺(aq) + 3SO₄²⁻(aq)
I/mol·L⁻¹: 0.26 0 0
C/mol·L⁻¹: -0.26 +0.52 +0.84
E/mol·L⁻¹: 0 0.52 0.84
Answer:
12 amu or 12 g.
Explanation:
One mole of 12C = one 12c atom. The mass of one carbon-12 atom is 12.000 amu.
The given data states that the 2-D diagram is representing Lithium molecule.
few things one must know before solving the question,
Lithium is a Alkali metal having 3 electrons, out of which two electrons lies in 1S orbital (K shell) & one electron lies in 2S orbital. To attain the stability ( nobel configuration) lithium requires 7 electron which is not possible at ordinary condition & it requires a huge amount of energy instead lithium loses one electron from outermost shell.
We know that when any atom loses a electron the oxidation number is written with plus(+) symbol.
Hence net charge on lithium ion is +1
Density = mass / volume
To solve for volume, multiply both sides of the equation by volume. This will cancel volume on the right and place it on the left.
volume x density = mass / volume x volume
volume x density = mass
Now, divide both sides by the density.
volume x density / density = mass / density
In the end, density cancels out so:
Volume = mass / density