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3 years ago

6

a bevrage is made by mixing 3 parts of water with 5 parts of fruit juice how many parts of water are mixed with 1 part of fruit

juice

1 answer:

romanna [79]3 years ago

6 0

So the ratio is 3:5. Se need to find x:1 you do that by dividing each side by 5. 3/5 = .6

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a recipe of cookies uses 220 g of butter and 110 g of caster sugar and 275 grams of flour what is the ratio of sugar to flour to

andre [41]

Answer: 22 to 55 to 44

Step-by-step explanation: Start with the factors you know. It can't be two because 2 doesn't go into 275 evenly. It can't be three because all of them evenly don't go into three. It can't be four because 110 and 275 don't go into it evenly. But five works. 110/ 5 is 22, 275/ 5 is 55, and 220/ 5 is 44.

7 0

3 years ago

What's the equivalent algebraic expression?

densk [106]

-10c+70, just distribute the the -10 to everything in the expression

3 0

3 years ago

natima [27]

Answer:

b. 9

Step-by-step explanation:

36+97=133

80+44=124

133-124=9

4 0

2 years ago

Write in exponent form 85

Nataly [62]

We are given 85

Firstly, we will find all possible factors of 85

we can write it as

$85=1*5*17$

so, exponential form is

$85=5^1*17^1$ ................Answer

4 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago