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Gennadij [26K]
3 years ago
6

11x+4y=-46 7x-4y=10 Find x and y

Mathematics
1 answer:
UNO [17]3 years ago
3 0

Answer:x=-2 y=-6

Step-by-step explanation:

11x+4y=-46..........(1)

7x-4y=10..............(11)

Add (1) and (11)

11x+7x+4y-4y=-46+10

18x=-36

Divide both sides by 18

18x/18=-36/18

x=-2

substitute x=-2 in (11)

7x-4y=10

7(-2)-4y=10

-14-4y=10

Collect like terms

4y=-14-10

4y=-24

Divide both sides by 4

4y/4=-24/4

y=-6

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22% of all resumes received by a corporation for a management position are from females. 18 resumes will be received tomorrow.
Vladimir79 [104]

Answer:

5.80% probability that exactly 1 resume will be from females.

Step-by-step explanation:

For each resume received by the corporation, there are only two possible outcomes. Either they are from a female, or they are not. The probability of a resume received being from a female is independent from other resumes. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

22% of all resumes received by a corporation for a management position are from females.

This means that p = 0.22

18 resumes will be received tomorrow.

This means that n = 18

What is the probability that exactly 1 resume will be from females?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{18,1}.(0.22)^{1}.(0.78)^{17} = 0.0580

5.80% probability that exactly 1 resume will be from females.

3 0
3 years ago
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Step-by-step explanation:

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