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alukav5142 [94]
3 years ago
12

Write logbx + logby - logbz as a single logarithm.

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0
Logbx+logby-logbz
=logb(x*y)/z if b is the base of log.
There are two properties that you can apply to get the correct answer.
logb(x*y)=logbx+logby if b is the base of log.
logb(x/y)=logbx-logby if b is the base of log, so the correct answer for logbx+logby-logbz=logb(x*y)/z. Hope it help!
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Find the sum of the following infinite geometric series, if it exists.
Paha777 [63]
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4 0
3 years ago
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the first box measures 18 inches by 8 inches by 15 inches. the second box is 10 inches tall and the area of the base measures 19
Mandarinka [93]

Answer:

  Box 1 has the greater volume, by 200 in³

Step-by-step explanation:

The largest of two volumes can be found by computing each volume and comparing the results.

<h3>Box 1</h3>

The volume is computed from dimensions by ...

  V = LWH

  V = (18 in)(8 in)(15 in) = 2160 in³

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<h3>Box 2</h3>

The volume is computed from area and height by ...

  V = Bh . . . . . where B is the base area, and h is the height

  V = (196 in²)(10 in) = 1960 in³

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<h3>Comparison</h3>

The units of the two volumes are the same, so we can decide which is larger by comparing the numbers. Box 1 has a volume that is more than 2000 in³, and Box 2 has a volume that is less than 2000 in³.

  Box 1 has a greater volume

The amount by which the volume is greater can be found by subtracting the smaller volume from the larger:

  2160 in³ -1960 in³ = 200 in³

  Box 1 is larger by 200 in³

_____

<em>Additional comment</em>

The percentage by which Box 1 is larger than Box 2 can be found by multiplying 100% by the ratio of the difference to the Box 1 volume:

  200/1960 × 100% ≈ 10.2%

Box 1 is about 10% larger than Box 2.

3 0
2 years ago
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Write a word problem that can be solved by ordering 3 decimals to thousand include a solution
IrinaK [193]

Answer:

I have no clue but this was two years ago so hopefully you know the answer by now

Step-by-step explanation:

yes

6 0
3 years ago
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
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What's slope Line<br> pass through( 14, 4)( 21, 6
Svet_ta [14]
What's slope Line
pass through( 14, 4)( 21, 6 Answer :m=2/7
5 0
3 years ago
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