Answer:
6Y
Step-by-step explanation:
We need to solve the statement ' Thrice the product of two and "Y" '.
Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.
Let the result is R. It can be calculated as follows :

We know that, 3×2 = 6
So,

Hence, Thrice the product of two and "Y" is 6Y.
Look this up
On quizlet it will give you the answer
Answer:
ki.f,gxjnbvb
Step-by-step explanation:b nn n vhhhvb bhv hv
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614