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Anastaziya [24]
3 years ago
6

A person produces two sound waves with a flute one immediately after the other. Both sound waves have the same pitch, but the se

cond one is louder. Which of the following properties is greater for the second sound wave?
A) Frequency
B) Amplitude
C) Wavelength
D) Speed in air

Physics
1 answer:
stealth61 [152]3 years ago
4 0

Answer:

Option B is the right choice.

Explanation:

Given:

Two sounds waves lets say S_1 and S_2 having same pitch but

We have to find the property which from the options and identify which one is greater for S_2 .

Lets take one and one analysis of the terms.

a.

Frequency :

  • It is how fast the sound wave is oscillating.
  • Frequency is f=\frac{1}{T} hertz.
  • The faster the sound wave oscillates the higher pitch it will have.

According to the question the pitch is same so the frequency will be same for both the waves.

b.

Amplitude :

  • The loudness of the sound increases with an increase in the amplitude of sound waves.
  • It is the maximum amount of displacement of a particle on the medium from its rest position.

c.

Wavelength :

  • Distance between two consecutive crest (high) or trough (low) is called wavelength.
  • Shorter wavelength will have higher frequency.

Here the frequency is same so the wavelength for S_1,S_2 will be same.

d.

Speed in air:

  • Speed of sound in a same medium is usually same.
  • Speed of sound in air is 343 m/s.

So,

Amplitude of S_2 > S_1 .

Here the amplitude of the louder sound wave will be greater .

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Sav [38]
Good morning.

We see that \mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}

The magnitude(norm, to be precise) can be calculated the following way:

\star \ \boxed{\mathsf{\overset{\to}{a}=(x, y,z)\Rightarrow ||\overset{\to}{a}|| = \sqrt{x^2+y^2+z^2}}}


Now the calculus is trivial:

\mathsf{\|\overset{\to}{b} \| =\sqrt{4^2+4^2+2^2} =\sqrt{16+16+4}}\\ \\ \mathsf{\|\overset{\to}{b}\|=\sqrt{36}}\\ \\ \boxed{\mathsf{\|\overset{\to}{b}\| = 6.00 \ u}}
7 0
3 years ago
It is claimed that if a lead bullet goes fast enough, it can melt completely when it comes to a halt suddenly, and all its kinet
Amiraneli [1.4K]

Answer:

354.72 m/s

Explanation:

m = mass of lead bullet

c = specific heat of lead = 128 J/(kg °C)

L = Latent heat of fusion of lead = 24500 J/kg

T_{i} = initial temperature = 27.4 °C

T_{f} = final temperature = melting point of lead =  327.5 °C

v = Speed of lead bullet

Using conservation of energy

Kinetic energy of bullet = Heat required for change of temperature + Heat of melting

(0.5) m v^{2} = m c (T_{f} - T_{i}) + m L\\(0.5) v^{2} = c (T_{f} - T_{i}) + L\\(0.5) v^{2} = (128) (327.5 - 27.4) + 24500\\(0.5) v^{2} = 62912.8\\v = 354.72 ms^{-1}

3 0
3 years ago
A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At
GuDViN [60]

Answer:

E/4

Explanation:

The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

Where;

E is the electric field

σ is the surface charge density

ε₀ is the electric constant.

Formula to calculate σ is;

σ = Q/A

Where;

Q is the total charge of the sheet

A is the sheet's area.

We are told the elastic sheet is a square with a side length as d, thus ;

A = d²

So;

σ = Q/d²

Putting Q/d² for σ in the electric field equation to obtain;

E = Q/(2ε₀d²)

Now, we can see that E is inversely proportional to the square of d i.e.

E ∝ 1/d²

The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.

From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;

E_new = E/4

3 0
3 years ago
An airplane flying due north at 90km/h is being blown due west at 50 km/h. What is the magnitude of the resultant velocity of th
Vlada [557]

Answer: 103 km/hr

Explanation:

Guessed on ck-12 and it ended up being right.

5 0
3 years ago
Consider a box weight 2700 newtons resting on the ground. If the area of the box touching the ground is 1.5 square meters, what
Neko [114]

Answer:

The answer to your question is 1800 Pa

Explanation:

Data

Weight = 2700 N

Area = 1.5 m²

Pressure = ?

Formula

Pressure = Force / Area

The Pressure is defined as the force exerted per unit area.

-Substitution

 Pressure = 2700 / 1.5

-Result

 Pressure = 1800 Pa

The units of pressure are Pascals (Pa)

6 0
3 years ago
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