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Anastaziya [24]
2 years ago
6

A person produces two sound waves with a flute one immediately after the other. Both sound waves have the same pitch, but the se

cond one is louder. Which of the following properties is greater for the second sound wave?
A) Frequency
B) Amplitude
C) Wavelength
D) Speed in air

Physics
1 answer:
stealth61 [152]2 years ago
4 0

Answer:

Option B is the right choice.

Explanation:

Given:

Two sounds waves lets say S_1 and S_2 having same pitch but

We have to find the property which from the options and identify which one is greater for S_2 .

Lets take one and one analysis of the terms.

a.

Frequency :

  • It is how fast the sound wave is oscillating.
  • Frequency is f=\frac{1}{T} hertz.
  • The faster the sound wave oscillates the higher pitch it will have.

According to the question the pitch is same so the frequency will be same for both the waves.

b.

Amplitude :

  • The loudness of the sound increases with an increase in the amplitude of sound waves.
  • It is the maximum amount of displacement of a particle on the medium from its rest position.

c.

Wavelength :

  • Distance between two consecutive crest (high) or trough (low) is called wavelength.
  • Shorter wavelength will have higher frequency.

Here the frequency is same so the wavelength for S_1,S_2 will be same.

d.

Speed in air:

  • Speed of sound in a same medium is usually same.
  • Speed of sound in air is 343 m/s.

So,

Amplitude of S_2 > S_1 .

Here the amplitude of the louder sound wave will be greater .

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CaHeK987 [17]

Answer:

<h2>Magnetic field required for the given induced EMF is 1.41 T</h2>

Explanation:

Potential difference across the blood vessel is given as

E = vBd

here we know that the speed is given as

v = 14.8 cm/s

d = 4.80 mm

E = 1 mV

now we have

1 \times 10^{-3} = (14.8 \times 10^{-2})B(4.80 \times 10^{-3})

B = 1.41 T

Now volume flow rate of the blood is given as

Q = Av

Q = \frac{\pi d^2v}{4}

from above equation we have

v = \frac{E}{Bd}

Now we have

Q = \frac{\pi d^2\frac{E}{Bd}}{4}

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5 0
2 years ago
A bowling ball of mass 5.8 kg moves in a straight line at 4.34 m/s How fast must a Ping-Pong ball of mass 2.214 g move in a stra
lilavasa [31]

Answer: 11369.46 m/s

Explanation:

We have the following data:

m_{1}=5.8 kg is the mass of the bowling ball

V_{1}=4.34 m/s is the velocity of the bowling ball

m_{2}=2.214 g \frac{1 kg}{1000 g}=0.002214 kg is the mass of the ping-pong ball

V_{2} is the velocity of the ping-pong ball

Now, the momentum p_{1} of the bowling ball is:

p_{1}=m_{1}V_{1} (1)

p_{1}=(5.8 kg)(4.34 m/s)  

p_{1}=25.172 kg m/s (2)

And the momentum p_{2} of the ping-pong ball is:

p_{2}=m_{2}V_{2} (3)

If the momentum of the bowling ball is equal to the momentum of the ping-pong ball:

p_{1}=p_{2} (4)

m_{1}V_{1}=m_{2}V_{2} (5)

Isolating V_{2}:

V_{2}=\frac{m_{1}V_{1}}{m_{2}} (6)

V_{2}=\frac{25.172 kg m/s}{0.002214 kg} (7)

Finally:

V_{2}=11369.46 m/s

6 0
2 years ago
How do you solve this???
Tom [10]
Rt= ΣR = 40Ω
Vt= 80V
It= 80V/40Ω= 2A
V1= 15Ω*2A= 30V
V2= 20Ω*2A= 40V
V3= 5Ω*2A= 10V
4 0
3 years ago
How are wave properties and energy related?<br> EXPLAIN
dexar [7]

Answer:

The higher the amplitude, the higher the energy. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

6 0
2 years ago
A force is represented by a ____ the choice of a ____ is necessary​
Vlad [161]

Answer:

a force is represented by a<u> vector </u>the choice of a <u>reference frame</u> is necessary​

Explanation:

3 0
2 years ago
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