A rubber block weighing 60. newtons is resting on a horizontal surface of dry asphalt. what is magnitude of the minimum force ne
1 answer:
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Answer:
k = 5.05 N/m
Explanation:
In order to calculate the spring mass of the system, you use the following formula:
(1)
T: period of oscillation of the system
m: mass of the air-track glider = 200g = 0.200 kg
k: spring constant = ?
You first calculate the period of oscillation:
Next, you solve the equation (1) for k, and then you replace the values of the other parmateres:
The spring constant of the spring is 5.05 N/m
Answer:
(a) Time will be t = 3.56 sec
(b) Distance traveled by car when they are side by side is 37.38712 m
(b) Velocity of race car = 21.004 m/sec
velocity of stock car = 12.816 m/sec
Explanation:
We have given acceleration of the car
Acceleration of the stock car
When 1st car overtakes the second car then distance traveled by both the car will be same
(a) So
As both car starts from rest so initial velocity of both car will be 0 m/sec
It is given that stock car leaves 1 sec before
So
After solving t = 3.56 sec
(b) From second equation of motion
(c) From first equation pf motion v = u+at
So velocity of race car v = 0+5.9×3.56 = 21.004 m/sec
Velocity of stock car v = 0+ 3.6×3.56 = 12.816 m/sec