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3 years ago

The pressure exerted by a gas on its container is directly proportional to ________.

1 answer:

6 0

<span>The pressure exerted by a gas on its container is directly proportional to the absolute temperature of the gas.

This result is known as "Gay-Lussac law", which states that for an ideal gas with fixed volume (like the gas in the container), the ratio between pressure and absolute temperature of the gas is constant:
</span> $\frac{p}{T}=k$
<span>where p is the pressure of the gas and T its absolute temperature.</span>

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An object dropped from Cliff falls with a constant acceleration of 10 metre per second square find its Speed of two seconds afte

julsineya [31]

Answer:

20 meters per second

Explanation:

If an object accelerates for 2 seconds, and accelerates by 10 meters per second, then that objects speed will be 20 meters per second, assuming hat there are no other factors involved.

3 0

2 years ago

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You look at a barometer and see that the air pressure is getting much higher... How will the weather probably change? *

Murljashka [212]

Answer:

The weather will clear up and get sunnier.

Explanation:As weather forecasters monitor air pressure, falling barometer measurements can signal that bad weather is on the way. In general, if a low pressure system is on its way, be prepared for warmer weather with storms and rain. If a high pressure system is coming, you can expect clear skies and cooler temperatures.

hope this helped:)

Brainliest?

8 0

2 years ago

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a bullet with a mass of 4.0g and a speed of 650m/s is fired at a block of wood with a mass of 0.095kg. the block rests on a fric

n200080 [17]

Part a)

Here in this we can use momentum conservation as there is no external force on it

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} +m_2v_{2f}$

here we know that

$m_1 = 0.004 kg$

$v_{1i} = 650 m/s$

$m_2 = 0.095$

$v_{2i} = 0$

$v_{2f} = 23 m/s$

now by above equation

$0.004*650 + 0.095* 0 = 0.004*v + 0.095*23$

$2.6 + 0 = 0.004*v + 2.185$

$v = 103.75 m/s$

Part b)

Final kinetic energy of the system

$KE_f = \frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2$

$KE_f = \frac{1}{2}*0.004*(103.75^2) + \frac{1}{2}*(0.095)*23^2$

$KE_f = 46.65 J$

Initial Kinetic energy of the system will be

$KE_f = \frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2$

$KE_f = \frac{1}{2}*0.004*(650^2) + \frac{1}{2}*(0.095)*0^2$

$KE_f = 845 J$

So here kinetic energy is decreased for this system

final energy is less than initial energy

6 0

2 years ago

A rocket moves upward, starting from rest with an acceleration of +29.4 for 3.98 s. it runs out of fuel at the end of the 3.98 s

topjm [15]

U = 0, initial upward speed
a = 29.4 m/s², acceleration up to 3.98 s
a = -9.8 m/s², acceleration after 3.98s

Let h₁ = the height at time t, for t ≤ 3.98 s
Let h₂ = the height at time t > 3.98 s

Motion for t ≤ 3.98 s:
h₁ = (1/2)*(29.4 m/s²)*(3.98 s)² = 232.854 m
Calculate the upward velocity at t = 3.98 s
v₁ = (29.4 m/s²)*(3.98 s) = 117.012 m/s

Motion for t > 3.98 s
At maximum height, the upward velocity is zero.
Calculate the extra distance traveled before the velocity is zero.
(117.012 m/s)² + 2*(-9.8 m/s²)*(h₂ m) = 0
h₂ = 698.562 m

The total height is
h₁ + h₂ = 232.854 + 698.562 = 931.416 m

Answer: 931.4 m (nearest tenth)

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3 years ago

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If element x has 10 electrons, how many of them will be in the second energy level?

Sati [7]

the second level will have 8 electrons.

6 0

2 years ago