Explanation:
It is given that,
Height above which the stone was thrown, h = 10 m
Initial velocity of the stone, u = 8 m/s
Angle above the horizontal, 
The horizontal component of velocity is, 
The vertical component of velocity is, 
Let t is the time of flight in vertical motion. The second equation of motion is :
t = 0.34 seconds
Let s is the range of the stone. It can be calculated as :
s = 2.46 meters
So, the range of the stone is 2.46 meters. Hence, this is the required solution.
Answer:
Ans 171.875 m(according to the units)
Explanation:
As we know,
to find the distance, we need to use this eqn..
speed = distance/ time
So, time is 1.92 s (as given)
the speed is 330 m/s ( in air speed)
so to find it is easy to find by using this
eqn..
speed =distance/time
330 =distance/1.92
330/1.92 =distance
171.875 = distance
i think number 1 on the bottom is friction, i honestly am having trouble myself so i cannot really help
The 1st one is basically B because it will stay in motion with the same speed and in the same direction unless acted on by an unbalanced force and the 2cd one is A because most of is transformed into thermos energy. hope this helps!
Answer: 7
Explanation:
I might be wrong but let me know if it is or not.
