All categories

3 years ago

What point is the image of (3,4) if it is reflected over the y axis?A. (-3,-4)B. (3,-4)C. (-3,4)D. (3,4)

Mathematics

1 answer:

frutty [35]3 years ago

6 0

Point is the image of (3,4) if it is reflected over the y axis is (-3,4)
answer
C. (-3,4)

You might be interested in

Write an expression that represents n plus 7 multiplied by 3.

diamong [38]

The expression that represents n plus 7 multiplied by 3 is
(n + 7)(3)
The entire expression, (n + 7) is multiplied by 3 since it would be inconvenient to state the expression as given above if what is meant was
(n + 7x3). It would have simply been n plus 21.

7 0

3 years ago

Read 2 more answers

Help asap!!!!!!!!!!!!!!!!!!!!!!! 20 points!1

Darya [45]

Answer:

Step-by-step explanation:

8 0

3 years ago

Find the 5th (not fourth) of given geometric sequence. 2000, 1000, 500,...

Greeley [361]

Answer:

125

Step-by-step explanation:

To find the common ratio, take the second term and divide by the first term

1000/2000 = 1/2

We multiply each term by 1/2

2000, 1000, 500

To find the next term 500*1/2 = 500/2 = 250

To find the 5th term

250*1/2 = 125

8 0

3 years ago

What is the answer to this??/

Alja [10]

Answer:

The median dr smith is 15

Step-by-step explanation:

7 0

3 years ago

F(x) = e^-x . Find the equation of the tangent to f(x) at x=-1

natima [27]

Answer:

The equation of the tangent line is given by the following equation:

$\displaystyle y - \frac{1}{e} = \frac{-1}{e} \bigg( x - 1 \bigg)$

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

*Note:

Recall that the definition of the derivative is the slope of the tangent line.

Step 1: Define

Identify given.

$\displaystylef(x) = e^{-x} \\x = -1$

Step 2: Differentiate

[Function] Apply Exponential Differentiation [Derivative Rule - Chain Rule]:
$\displaystyle f'(x) = e^{-x}(-x)'$
[Derivative] Rewrite [Derivative Rule - Multiplied Constant]:
$\displaystyle f'(x) = -e^{-x}(x)'$
[Derivative] Apply Derivative Rule [Derivative Rule - Basic Power Rule]:
$\displaystyle f'(x) = -e^{-x}$