This is a
redox reaction where oxidation and a reduction occur.
<span>Here, Mg goes to Mg²</span>⁺ <span>by changing
its oxidation
number from 0 to +2 while S goes
to S²</span>⁻ <span>by reducing its oxidation
state from 0 to -2 .
Hence Mg is
oxidized by S in the
reaction.</span>
Reducing agent <span>is a substance which reduces other
substance by oxidizing itself. Hence, the reducing
agent of this reaction
is <span>Magnesium.</span></span>
The answer is D because the air is made of nitrogen and oxygen. The reaction is endothermic.
Hope this helps you! :)
Answer:
P₂ = 592.7 torr
Explanation:
Given data:
Initial Pressure = 215 torr
Initial volume = 51.0 mL
Final pressure = ?
Final volume = 18.5 mL
Solution:
P₁V₁ = P₂V₂
P₁ = Initial Pressure
V₁ = Initial volume
P₂ = Final pressure
V₂ = Final volume
Now we will put the values in formula.
P₁V₁ = P₂V₂
215 torr × 51.0 mL = P₂ × 18.5 mL
10965 mL. torr = P₂ × 18.5 mL
P₂ = 10965 mL. torr /18.5 mL
P₂ = 592.7 torr
Answer:
9 grams
Explanation:
Hope it can help you.....