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viktelen [127]
2 years ago
11

If oxygen is removed from a sample of air as iron nusts, what happens to the partial pressure of oxygen in the air?

Chemistry
1 answer:
trasher [3.6K]2 years ago
3 0

Answer:

It increases because the less oxygen the more pressure there will be on that specific object

Explanation:

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A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
3 years ago
Hello!! I need help please! Please explain how I can identify a percipitate in a reaction! I need help with chemistry ha
antiseptic1488 [7]
Generally speaking a precipitate is something that will form as a result of the reaction.  It generally is a solid material.

Sodium and nitrates are soluble so Calcium Phosphate would precipitate out....


5 0
2 years ago
What does energy have to do with reproduction
murzikaleks [220]

Answer:

Nutrition has a significant impact on numerous reproductive functions including hormone production, folliculogenesis, fertilization, and early embryonic development

Explanation:

This intimate association is because reproductive processes are energetically expensive, and the brain must temper the fertility of individuals to match nutritional availability.Reproduction function in mammals can be inhibited when food availability is low or when increased energy demands are not met by compensatory food intake such as in short-term and chronic withdrawal of nutrients.This very close alignment with the food supply is more important in females, where pregnancy and lactation are linked to considerable energetic expenses, needed for the nurture of embryos and newborns. In fact, her reproductive outcome can be seriously altered and even life threatening to both the mother and offspring when nutritional imbalance occurs. In order to keep constant body energy stores, in mammals, a series of homeostatic events leading to maintenance of energy balance are activate when a state of energy scarcity or abundance occurs.

6 0
2 years ago
A boy jumps into a cold swimming pool and his body temperature goes down. His muscles, blood vessels, and nervous system work to
mixas84 [53]

Answer:

balance

Explanation:

4 0
2 years ago
Sodium metal (Na) reacts explosively with water to form sodium hydroxide (NaOH) and hydrogen gas. How many moles of sodium are n
Sati [7]

Answer:

308 moles of sodium

Explanation:

The balanced equation for the chemical reaction between sodium metal (Na) and water (H₂O) is the following:

2 Na(s) + 2 H₂O → 2 NaOH(aq) + H₂(g)

From the equation, we can see that 2 moles of Na react with 2 moles of H₂O to give 2 moles of NaOH and 1 mol of H₂ (hydrogen gas). So the stoichiometric mole ratio between Na and H₂ is: 2 mol Na/1 mol H₂. Thus, we multiply the mole ratio by the moles of H₂ to be produced to obtain the moles of Na required:

moles of Na required =  2 mol Na/1 mol H₂ x 154 moles H₂ = 308 moles Na

Therefore, 308 moles of sodium are needed to produce 154 moles of hydrogen gas.

7 0
3 years ago
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