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Sauron [17]
2 years ago
5

Is a mountain a deconstructive process

Chemistry
1 answer:
blagie [28]2 years ago
6 0

Answer:

yes

Explanation:

i looked it up.........

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a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc
ladessa [460]

Answer:

The molarity of the solution is 1.1 \frac{moles}{liter}

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case

  • number of moles of solute= 0.564 moles
  • volume= 0.510 L

Replacing:

molarity=\frac{0.564 moles}{0.510 L}

Solving:

molarity= 1.1 \frac{moles}{liter}

<u><em>The molarity of the solution is 1.1 </em></u>\frac{moles}{liter}<u><em></em></u>

4 0
2 years ago
A container with a volume 2. 0 L is filled with a gas at a pressure of 1. 5 atm. By decreasing the volume of the container to 1.
worty [1.4K]

The resulting pressure of the gas after decreasing the initial volume from 2 L to 1 L is 3 atm.

<h3>What is Boyle's Law?</h3>

According to the Boyle's Law at constant temperature, pressure of the gas is inversely proportional to the volume of that gas.

For the given question we use the below equation is:

P₁V₁ = P₂V₂, where

P₁ = initial pressure of gas = 1.5 atm

V₁ = initial volume of gas = 2 L

P₂ = final pressure of gas = ?

V₂ = final volume of gas = 1 L

On putting all these values on the above equation, we get

P₂ = (1.5atm)(2L) / (1L) = 3 atm

Hence required pressure of the gas is 3 atm.

To know more about Boyle's Law, visit the below link:
brainly.com/question/469270

5 0
1 year ago
A 5.0 L sample of gas at 300. K is heated to 600. K. What will the new volume of the gas be?
Ainat [17]

Answer:

V_2=10L

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

\frac{V_2}{T_2} =\frac{V_1}{T_1}

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L

Regards!

4 0
2 years ago
What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?
Step2247 [10]

Answer:

\Delta \rho =2.22 g/mL

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

\Delta \rho=\rho _f-\rho _i\\ \\\Delta \rho=5.43g/mL-3.21g/mL\\\\\Delta \rho =2.22 g/mL

Best regards.

3 0
2 years ago
A gas has a volume of 52.1 L at 1.55 atm. What is the new volume at a pressure of 2.00 atm?
Deffense [45]

Answer: 40.38 L

Explanation:

Formula: P1V1 = P2V2

(1.55)(52.1) = (2.00)(x)

80.755 = 2x

40.38 = x

6 0
2 years ago
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