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Sauron [17]
3 years ago
5

Is a mountain a deconstructive process

Chemistry
1 answer:
blagie [28]3 years ago
6 0

Answer:

yes

Explanation:

i looked it up.........

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What is the name of this compound?<br> CH3CH2OCH2CH2CH3
WARRIOR [948]

The name of this compound is Ethyl propyl ether, CH3CH2OCH2CH2CH3 stands for Ethyl propyl ether.

8 0
4 years ago
Helpppppppppppppppppppppppppppppppppp
Alborosie

Answer:

the drops of liquid are coming from the decreases. they are formed as the motion of the water particles in the air gas. this change in motion cause air in the air to change from a liquid to a water

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3 years ago
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In the diagram of a transverse wave shown, what does P represent?
Effectus [21]
L is amplitude M is wavelength and P is frequency
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3 years ago
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If 4.0 g of helium gas occupies a volume of 22.4 L at 0 o C and a pressure of 1.0 atm, what volume does 3.0 g of He occupy under
WINSTONCH [101]

Answer:

the volume occupied by 3.0 g of the gas is 16.8 L.

Explanation:

Given;

initial reacting mass of the helium gas, m₁ = 4.0 g

volume occupied by the helium gas, V = 22.4 L

pressure of the gas, P = 1 .0 atm

temperature of the gas, T = 0⁰C = 273 K

atomic mass of helium gas, M = 4.0 g/mol

initial number of moles of the gas is calculated as follows;

n_1 = \frac{m_1}{M} \\\\n_1 = \frac{4}{4} = 1

The number of moles of the gas when the reacting mass is 3.0 g;

m₂ = 3.0 g

n_2 = \frac{m_2}{M} \\\\n_2 = \frac{3}{4} \\\\n_2 = 0.75 \ mol

The volume of the gas at 0.75 mol is determined using ideal gas law;

PV = nRT

PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\since, \ \frac{RT}{P} \ is \ constant,\  then;\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1n_2}{n_1} \\\\V_2 = \frac{22.4 \times 0.75}{1} \\\\V_2 = 16.8 \ L

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.

4 0
3 years ago
Convert mass to moles for both reactants. (round to 2 significant figures.)
Maslowich

Answer:

Explanation:

Given parameters:

Mass of CuCl₂  = 2.50g

Mass of Al  = 0.50g

Unknown:

Number of moles of CuCl₂ and Al  = ?

Solution:

To solve this problem, we must understand that the number of moles is a fundamental property used in stoichiometry calculations.

         Number of moles  = \frac{mass}{molar mass}

Molar mass of CuCl₂  = 63.6 + 2(35.5) = 134.5g/mole

Molar mass of Al  = 26.98g/mole

          Number of moles of  CuCl₂  = \frac{2.5}{134.5}  = 0.019moles

        Number of moles of Al  = \frac{0.5}{26.98}   = 0.019moles

4 0
3 years ago
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