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maks197457 [2]
3 years ago
14

PLEASE HELP, WILL MARK BRAINLIEST!!!!! TIME IS RUNNING OUT!!!!

Chemistry
1 answer:
faltersainse [42]3 years ago
6 0

This is a redox reaction where oxidation and a reduction occur.

<span>Here, Mg goes to Mg²</span>⁺ <span>by changing its oxidation number from 0 to +2 while S goes to S²</span>⁻ <span>by reducing its oxidation state from 0 to -2 . Hence Mg is oxidized by S in the reaction.</span>

 

Reducing agent <span>is a substance which reduces other substance by oxidizing itself. Hence, the reducing agent of this reaction is <span>Magnesium.</span></span>

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An acid sample of an unknown concentration is contained in a erlenmeyer flask. Which technique below would be best suited to ana
Ivenika [448]

Answer:

Titration

Explanation:

The best technique which can be used to determine the number of moles of the HCl in the sample is titration.

The given amount of HCl solution must be titrated with known concentration of the base like NaOH.

The volume of NaOH required must be noted also.

According to the reaction,

NaOH+HCl\rightarrow NaCl+H_2O

At equivalence point

Moles of HCl = Moles of NaOH

Considering:-

Moles of HCl=Molarity_{NaOH}\times Volume_{NaOH}

Thus, in this way, moles of HCl can be determined.

4 0
2 years ago
Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.
Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}

Converting moles of boric acid to mass:

0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}}   = 6.183 g

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.


5 0
3 years ago
Why is it important for the kitchen manager to make sure food is fresh?
netineya [11]
Cause some ingredients might be expired and someone might get poisoned
6 0
2 years ago
What is the vapor pressure of a liquid at 305.03 K if its ∆Hvap = 28.9 kJ/mol and its normal boiling point is 341.88 K?
ASHA 777 [7]

<u>Answer:</u> The vapor pressure of the liquid is 0.293 atm

<u>Explanation:</u>

To calculate the vapor pressure of the liquid, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm

P_2 = pressure of the liquid = ?

\Delta H_{vap} = Heat of vaporization = 28.9 kJ/mol = 28900 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 341.88 K

T_2 = final temperature = 305.03 K

Putting values in above equation, we get:

\ln(\frac{P_2}{1})=\frac{28900J/mol}{8.314J/mol.K}[\frac{1}{341.88}-\frac{1}{305.03}]\\\\\ln P_2=-1.228atm\\\\P_2=e^{-1.228}=0.293atm

Hence, the vapor pressure of the liquid is 0.293 atm

5 0
2 years ago
What does the Law of conservation of matter say
KATRIN_1 [288]

Answer: during a chemical reaction, matter cannot be created or destroyed

Explanation:

3 0
3 years ago
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