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3 years ago

#8 please explain if you can thanks

Chemistry

1 answer:

pav-90 [236]3 years ago

6 0

The answer is D because the air is made of nitrogen and oxygen. The reaction is endothermic.
Hope this helps you! :)

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Step I of the proposed mechanism involves the collision between NO2 and F2 molecules. This step is slow even though such collisi

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Explanation:

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3 years ago

Calculate the molality and van’t Hoff factor (i) for the following aqueous solutions:

MissTica

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<h3>What is the value of Van t Hoff factor?</h3>

For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

<h3>Which has highest Van t Hoff factor?</h3>

The Van't Hoff factor will be highest for

A. Sodium chloride.

B. Magnesium chloride.

C. Sodium phosphate.

D. Urea.

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2 years ago

In many of the steps in the lab, a mixture was centrifuged and then decanted. In general terms, what is accomplished by these st

nirvana33 [79]

Answer:

to separate the compounds by gravity

Explanation:

Centrifuging is the process of separating compound in a liquid mixture by means of gravity and settling. This makes use of the density principle. In the process, the sample is added to the centrifuge. This is then rotated at a certain speed, say 50 rpm. The circular motion creates a force of gravity that pulls the compounds downwards. This then separate the compounds. The heaviest and most dense go down first, then the lighter particles on the top.

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3 years ago

You are given 25.00 mL of an acetic acid solution of unknown concentration. You find it requires 35.75 mL of a 0.1950 M NaOH sol

oee [108]

Answer:

0.2788 M

1.674 %(m/V)

Explanation:

Step 1: Write the balanced equation

NaOH + CH₃COOH → CH₃COONa + H₂O

Step 2: Calculate the reacting moles of NaOH

$0.03575 L \times \frac{0.1950mol}{L} = 6.971 \times 10^{-3} mol$

Step 3: Calculate the reacting moles of CH₃COOH

The molar ratio of NaOH to CH₃COOH is 1:1.

$6.971 \times 10^{-3} molNaOH \times \frac{1molCH_3COOH}{1molNaOH} = 6.971 \times 10^{-3} molCH_3COOH$

Step 4: Calculate the molarity of the acetic acid solution

$M = \frac{6.971 \times 10^{-3} mol}{0.02500L} =0.2788 M$

Step 5: Calculate the mass of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

$6.971 \times 10^{-3} mol \times \frac{60.05g}{mol} =0.4186 g$

Step 6: Calculate the percentage of acetic acid in the solution

$\frac{0.4186g}{25.00mL} \times 100\% = 1.674 \%(m/V)$

6 0

3 years ago

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A solution is prepared by dissolving 4.40 g of KSCN in enough water to make 200 mL of solution. What is the concentration of the

attashe74 [19]

First find the number of moles of KSCN is in 4.40g of KSCN 1. Number of moles = mass given (4.40g) / molecular weight(MW) (KSCN) - to calculate MW, look for each element in the periodic table and add their atomic weight 2. Convert 200mL to liters 3. Concentration = number of moles/ volume in liters from (#2)

4 0

3 years ago

Read 2 more answers