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3 years ago

Using the solubility curve, what is the effect of increased temperature on the solubility of KBr in 100 grams of water?

2 answers:

4 0

Here, Curve is nor provided but in general, Increase in Temperature increases the solubility of the solution, so it would be increase
(Brainliest please)

Archy [21]3 years ago

4 0

The solubility increases.

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Why does the temperature decrease when you do an endothermic reaction ?

lianna [129]

Answer:

Endothermic reactions often produce a decrease in temperature. In endothermic reactions, the bond energies of the reactants are greater than the bond energies of the products. ... This often causes a decrease in the temperature of the reaction mixture. All endothermic reactions absorb energy.

Explanation:

8 0

4 years ago

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The mole fraction of a non electrolyte (MM 101.1 g/mol) in an aqueous solution is 0.0194. The solution's density is 1.0627 g/mL.

yanalaym [24]

Answer:

Molarity for the solution is 1.05 mol/L

Explanation:

Mole fraction of solute = 0.0194

Solution's density = 1.0627 g/mL

We must know that sum of mole fraction = 1

Mole fraction of solute + Mole fraction of solvent = 1

0.0194 + Mole fraction of solvent = 1

Mole fraction of solvent = 1 - 0.0194 → 0.9806

Molarity is mol of solute in 1L of solution, so we have to determine solution's volume in L

With molar mass we can determine the mass of solute and solvent and then, the solution's mass

0.0194 mol . 101.1 g/ mol = 1.96 g of non electrolyte solute

0.9806 mol . 18 g/mol = 17.65 g of water

Mass of solution = mass of solute + mass of solvent

1.96 g + 17.65 g = 19.6 g (mass of solution)

Solution's density = Solution's mass / Solution's volume

1.0627 g/mL = 19.6 g / Solution's volume

Solution's volume = 19.6 g / 1.0627 g/mol →18.4 mL

Let's convert the mass from mL to L

18.4mL . 1L / 1000 mL = 0.0184 L

We have the moles of solute, so let's determine molarity

mol/L → 0.0194 mol / 0.0184 L = 1.05 M

8 0

3 years ago

A substance in the solid phase state of matter has

ElenaW [278]

Answer:

A variable shape that adapts to fit its container.

8 0

4 years ago

Stoichiometry. Are my answers right?

OverLord2011 [107]

Answer:

Congratulations. Mostly correct.

Step-by-step explanation:

Part I. Gold

Moles of Au = 35.12 2g × 1/196.97 = 0.1783 mol Au

Atoms of Au = 0.1783 × 6.022 × 10²³/1 = 1.074 × 10²³ atoms Au

Part II. Sucrose

Molar mass = 342.30 g/mol

Moles of C₁₂H₂₂O₁₁ = 1.202 g × 1/342.30

Moles of C₁₂H₂₂O₁₁ = 0.003 512 mol C₁₂H₂₂O₁₁

Moles of C = 0.003 512 × 12/1 = 0.042 14 mol C

Moles of H = 0.003 512 × 22/1 = 0.077 25 mol H

Moles of O = 0.003 512 × 11/1 = 0.038 63 mol O

Atoms of C = 0.042 14 × 6.022 × 10²³ = 2.538 × 10²² atoms C

Atoms of H = 0.077 25 × 6.022 × 10²³ = 4.652 × 10²² atoms H

Atoms of O = 0.038 63 × 6.022 × 10²³ = 2.326 × 10²² atoms O

<em>Minor Quibbles: </em>

You put the moles of sucrose in the molar mass slot.

You got the wrong exponents for the atoms of C, H, O.

You followed the rules for significant figures for gold, but not for sucrose.

6 0

4 years ago

Which of the following is an example of acceleration?

Elenna [48]

A car speeds up is acceleration

7 0

3 years ago

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