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jok3333 [9.3K]
3 years ago
14

What type of machine is a ramp for wheelchairs?

Chemistry
2 answers:
kap26 [50]3 years ago
5 0
C. a simple machine. 
My name is Ann [436]3 years ago
4 0
ANSWER: C. Simple machine 
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In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid
Zina [86]

The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

CV = C_{1}V_{1} + C_{2}V_{2}    (1)      

Where:

C: is the concentration if the mixture = 36%  

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

V = V_{1} + V_{2}

V_{2} = V - V_{1}  (2)

By entering equation (2) into (1), we have:

CV = C_{1}V_{1} + C_{2}(V - V_{1})

36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})

Changing the percent values to decimal ones:

0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})  

Now, by solving the above equation for V₁:

V_{1} = 74.27 mL  

Therefore, the volume of the 39% acid solution is 74.27 mL.

       

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!  

         

7 0
2 years ago
Read 2 more answers
dinitrogen pentoxide decomposes to form nitrogen dioxide oxygen, following the equation 2N2O5 -> 4NO2. at a certain time poin
Temka [501]

Rate of production of NO₂ = 0.2 M/s

Rate of production of O₂ = 0.05 M/s

<h3>Further explanation</h3>

Given

The rate of N₂O₅ : 0.1 M/s

Reaction

2N₂O₅⇒4NO₂+O₂

Required

The rate of production of NO₂ and O₂ at the same time point

Solution

Rate of disappearance of N₂O₅ = reaction rate x coefficient of N₂O₅

0.1 M/s=reaction rate x 2

<em>reaction rate = 0.05 M/s</em>

The rate of production of NO₂=

Rate of production of NO₂ = reaction rate x coefficient of NO₂

Rate of production of NO₂ = 0.05 M/s x 4

Rate of production of NO₂ = 0.2 M/s

The rate of production of O₂=

Rate of production of O₂ = reaction rate x coefficient of O₂

Rate of production of O₂ = 0.05 M/s x 1

Rate of production of O₂ = 0.05 M/s

5 0
3 years ago
Read 2 more answers
Which property of matter is conserved in chemical reactions and shown by balanced equations? mass volume density shape
den301095 [7]

Answer:mass

Explanation:

I took the quiz

3 0
3 years ago
Read 2 more answers
The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound exhibit
Masja [62]

Answer:

B.

Explanation:

3 0
2 years ago
25 L of a gas is collected at 115 kPa. If the pressure increases to 300 kPa, what is the new volume?
Lina20 [59]

Answer:

V2 = 9.58 Litres.

Explanation:

Given the following data;

Initial volume = 25 L

Initial pressure = 115 kPa

Final pressure = 300 kPa

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the equation, we have;

115 * 25 = 300*V_{2}

2875 = 300*V_{2}

V_{2} = \frac {2875}{300}

V_{2} = 9.58

V2 = 9.58 L

Therefore, the new volume is 9.58 litres.

5 0
2 years ago
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