Is it is it possible to have 43 pencils and divide the pencils into groups with the same number of pencils with none left over
2 answers:
we have given 43 pencils
we need to divide it equally so that none can be without groups.
we need to find the factors of 43.
we know that 43 is a prime number. which cannot be divided.so it is not possible to divide the 43 pencils with none left over .
TO find out the answer, we need to check whether 43 have any factors or not
43 is a prime number that is it have only two factors 1 and 43 . So either 1 will take whole 43 pencils or 43 will take one pencil each .
So it is not possible to divide 43 pencils into groups with the same number of pencils and none left over .
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