Answer:
Explanation:
work done by gravitational force during fall of distance d = mgd
work done by drag = w ( let )
mgd - w = 1/2 m v²
w = m g d - 1/2 m v²
so work done by drag force
= m g d - 1/2 m v²
b ) when terminal velocity is reached , drag force = mg
power supplied by drag force = force x velocity
= mg x v
P_d = mgv
Answer:
-34.5 W
Explanation:
rate of heat transfer = Stefan-Boltzmann constant x emissivity x surface area x temperature^4

False it’s the unit of force
Answer:
Original speed of the mess kit = 4.43 m/s at 50.67° north of east.
Explanation:
Let north represent positive y axis and east represent positive x axis.
Here momentum is conserved.
Let the initial velocity be v.
Initial momentum = 4.4 x v = 4.4v
Velocity of 2.2 kg moving at 2.9 m/s, due north = 2.9 j m/s
Velocity of 2.2 kg moving at 6.8 m/s, 35° north of east = 6.9 ( cos 35i + sin35 j ) = 5.62 i + 3.96 j m/s
Final momentum = 2.2 x 2.9 j + 2.2 x (5.62 i + 3.96 j) = 12.364 i + 15.092 j kgm/s
We have
Initial momentum = Final momentum
4.4v = 12.364 i + 15.092 j
v =2.81 i + 3.43 j
Magnitude

Direction

50.67° north of east.
Original speed of the mess kit = 4.43 m/s at 50.67° north of east.