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astra-53 [7]
4 years ago
10

What is the proper tool for cutting keyways or slots in metal?

Physics
1 answer:
Alika [10]4 years ago
6 0
I think it's a End milling of slots<span> </span>
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Small, slowly moving spherical particles experience a drag force given by Stokes' law: Fd = 6πηrv where r is the radius of the p
Dominik [7]

Answer:

Explanation:

At the time of a body achieving terminal velocity, the drag force becomes equal to the weight of the body less the buoyant force by the surrounding medium which can be represented by the following equation

\frac{4\pi\times r^3(d-\rho)}{3} =6\pi\times n\times r\times v

Where r is radius of the body , d is density of the material of the body σ is density of the medium and n is coefficient of viscosity of the medium and v is terminal velocity.

Simplifying

v = \frac{2\times r^2(d-\rho)}{9\times n}

Assuming the value of density of air as 1.225 kg/m³ and putting other given values in the formula we get

v = [tex]\frac{2\times (1.2\times10^{-5})^2(2182-1.225)}{9\times 1.8\times10^{-5}}[/tex]

v = 387 x 10⁻⁵ m/s

Terminal velocity = 387 x 10⁻⁵ m/s

Time taken to fall a distance of 100 m

= \frac{100}{387\times10^{-5}}

= 2.6 x 10⁴ s.

5 0
3 years ago
một hòn đá ném theo phương nằm ngang với vân tốc v0=15 m/s. tính gia tốc tiếp tuyến và gia tốc pháp tuyến của hòn đá sau lúc ném
Lady_Fox [76]

Answer:

what language is this???

5 0
3 years ago
when the heat is added to the material, which factors are important in order to determine how much the material will rise in tem
posledela

The heat Q transferred to cause a temperature change depends on the magnitude of the temperature change, the mass of the system, and the substance and phase involved.

Explanation:

https://courses.lumenlearning.com/physics/chapter/14-2-temperature-change-and-heat-capacity/

5 0
3 years ago
Distance meters Time (seconds) Trial Tria 2 Trials Average 3 053 059 0.52 055 6 106 719 104 Uning the values trom the data table
kumpel [21]
Jsisisusuagahannananana this is worth 22 points g that’s crazy 25
5 0
2 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
3 years ago
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