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GREYUIT [131]
3 years ago
9

It takes 130 J of work to compress a certain spring 0.10m. (a) What is the force constant of this spring? (b) To compress the sp

ring an additional 0.10 m, does it take 130 J, more than 130 J or less than 130 J? Verify your answer with a calculation.
Physics
1 answer:
Ede4ka [16]3 years ago
6 0

Explanation:

Given that,

Work done to stretch the spring, W = 130 J

Distance, x = 0.1 m

(a) We know that work done in stretching the spring is as follows :

W=\dfrac{1}{2}kx^2\\\\k=\dfrac{2W}{x^2}\\\\k=\dfrac{2\times 130}{(0.1)^2}\\\\k=26000\ N/m

(b) If additional distance is 0.1 m i.e. x = 0.1 + 0.1 = 0.2 m

So,

W=\dfrac{1}{2}kx^2\\\\W=\dfrac{1}{2}\times 26000\times 0.2^2\\\\W=520\ J

So, the new work is more than 130 J.

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A weather balloon has a volume of 35 L at sea level (1.0 atm). After the balloon is released it rises to where the air pressure
Mamont248 [21]

Answer:

P₁ = 1.0 atm

V₁ = 35 L

P₂ = 0.75 atm

Formula:

P₁V₁ = P₂V₂

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = (1.0 atm)(35 L) / 0.75 atm

V₂ = 47 L

Final Answer:

V₂ = 47 L

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2 years ago
The flywheel of a motor has a mass of 300.0 kg and a radius of 55 cm. If the motor can exert a torque of 2000.0 N . m on this fl
Alexeev081 [22]

Answer:

Explanation:

Work done by torque is given as

Word one = torque × angular displacement

W = ​ τ × θ

Given that,

τ = 2000Nm

Mass of motor = 300kg

Radius r = 55cm = 0.55m

Work done by wheel in first t= 23second.

Now we need to find the angular displacement

We know that,

τ = I•α

Moment of inertia of wheel

I = MR²

I = 300 × 0.55²

I = 90.75 kgm²

Then, τ = I•α

α = τ / I

α = 2000/90.75

α = 22.04rad/s²

Then, using circular motion,

∆θ = wit + ½αt²

wi = 0rad/s

∆θ = ½αt²

∆θ = ½ × 22.04 × 23²

∆θ = 5829.2 rad.

Then,

Work done?

W = ​ τ × θ

W = 2000 × 5829.2

W = 1.17 × 10 ^7 J

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