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jok3333 [9.3K]
3 years ago
8

Which statement about the equation is true?

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer:

The correct option is b) no solution.

Step-by-step explanation:

Consider the provided equation,

x + 2 = x + 4

We need to find the solution of the above equation.

Subtract x from both the sides as shown.

x-x+2=x-x+4

2=4

Which is false.

As 2 is not equal to 4.

Hence, the provided equation has no solution.

Thus, the correct option is b) no solution.

zvonat [6]3 years ago
6 0
C because you got to find the like term term
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The safest way for someone to make an online purchase is to
Elena-2011 [213]

Answer:

It is C - buy from a reputable website

Step-by-step explanation:

I got it right on the quiz. Good luck and may the Lord bless you!

4 0
3 years ago
Read 2 more answers
Find the length of the missing side in the figure below. a = _______ cm.
WITCHER [35]

Answer:

\frac{2 \sqrt{177} }{5}

or

5.32cm correct to 2 decimal places

Step-by-step explanation:

This is a right angled triangle from what I know so we have to apply pythagoras theorem.

{7.1}^{2}  =  {a}^{2}  +  {4.7}^{2}

we need to rearrange this to find a²

{a}^{2}  =  {7.1}^{2}  -  {4.7}^{2}

a =  \sqrt{ \frac{708}{25} }

This can either be written as a fraction or decimal.

a =  \frac{2 \sqrt{177} }{5}

OR

a = 5.32

correct to 2 decimal places

5 0
2 years ago
what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?
seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

0

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2

We we able to cancel out that factor that was giving us x=-4 is a zero.  

Therefore there is a hole at x=-4.

7 0
3 years ago
NEED HELP ASAP PLEASE
professor190 [17]
No idea sorry! If I knew I would tell you
7 0
1 year ago
Read 2 more answers
I need a step by step I got lost in learning
alexandr402 [8]

Answer:

6 to the power of 2.

Step-by-step explanation:

 Recall that whenever you divide exponents with the same base, you subtract the powers, but the base will still be the same. Therefore, 6 to the power of 12 divided by 6 to the power of 10 is 6 to the power of 2. Subtract the powers (exponents) or 12 minus 10, and you get 2. Since the base doesn't change, it is still 6. The solution to this expression is 6 to the power of 2. Hope this helps!

8 0
3 years ago
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