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luda_lava [24]
4 years ago
10

Please help!! 16 points !!!

Physics
1 answer:
labwork [276]4 years ago
3 0

Hey!

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\Large\boxed{\mathsf{Option~D}}

We can automatically eliminate option A and C because finding fossils isn't just trying to find the evolution of whales or bird. Archaeologists use fossils to see how animal evolve over a certain period of time. While they can build animals will the fossils they find but that isn't the most important use of fossils.

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\Large\boxed{\mathsf{Option~A}}

Typically scientists you radioactive dating to find how old a fossil. In this case that isn't an option. I chose option A because scientists can use shape of the fossil to determine what species its from and what part of the body it is.

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Hope This Helped! Good Luck!

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Bats are capable of navigating using the earth's field-a plus for an animal that may fly great distances from its roost at night
Nataliya [291]

Answer:

The correct magnitude of the coil's magnetic field= =50μT

Explanation :

The magnetic field takes place as a result of movement of charge I e current, can also occurs from magnetised material, magnetic field as a result of charge movement can be deducted using right hand grip rule.

At the equator magnetic field lines are parallel towards the earth's surface and the angle of inclination of the magnetic lines of force at the horizontal position is referred to as the angle of dip at the point.

As the current is produced then the varying magnetic field is opposed ,then there is induced current when the coil is positioned at varying magnetic field.

Given from the question,

angle below horizontal θ=60-degree

The Earth's magnetic field B=50μT

The horizontal magnetic field can be expressed in terms of the formula below;

BH=Bcos⁡θ

B(H) = earth's horizontal component of magnetic field

Ø is the angle between coil's field

B=the magnetic field in Tesla

Then,

BH=50μT×cos60∘

=50μT× 0.5

As the current is passed through the coil to produce a field , when combined with the earth's field, which creates a net field with the same strength and dip angle (60 degrees below horizontal) as the earth's field.

It can be deducted that B has the same magnitude and angle which makes the those vertical component to cancel each other since they are the same.

For the magnetic field to be pointed out at North direction, we can calculate the corrected magnetic field using the formula below

Bc=2BH

Bc=2×50μT× 0.5=50μT

The correct magnitude of the coil's magnetic field= =50μT

4 0
4 years ago
A car drives at a constant speed of 21 m/s around a circle of radius 100 m.
Arte-miy333 [17]

Answer:

Option D. 4.4 m/s²

Explanation:

The following data were obtained from the question:

Velocity (v) = 21 m/s

Radius (r) = 100 m

Centripetal acceleration (a) =.?

The centripetal acceleration of the car can be obtained as follow:

Centripetal acceleration (a) = Velocity square (v²) / radius (r)

a = v²/r

a = 21²/100

a = 441/100

a = 4.41 ≈ 4.4 m/s²

Therefore, the centripetal acceleration of the car is 4.4 m/s².

8 0
3 years ago
Describe the magnetic field in the vicinity of a bar magnet.
Lapatulllka [165]
Well both ends of the magnet have a diffrent magnetic force. i hope this was the answer you where looking for, and have a nice rest of the day

3 0
3 years ago
Read 2 more answers
A particle at 9 AM is moving towards the east at 4 ms At 12 noon, it changes its velocity and starts moving towards the north un
nexus9112 [7]

Answer:

Explanation:

Acceleration is the time rate of change of velocity.

Acceleration and velocity are vectors

If east and north are the positive directions, the east moving vector is reduced to zero and the north moving vector increases from zero to 4 m/s.

There are 3 hours or 10800 seconds between 10 AM and 1 PM

a1 = √((-4)² + 4²) / 10800 = (√32) / 10800 m/s² ≈ 4.2 x 10⁻⁴ m/s²

There are 14400 seconds between 10 AM and 2 PM

The velocity changes are still the same

a2 = √((-4)² + 4²) / 10800 = (√32) / 14400 m/s² ≈ 3.9 x 10⁻⁴ m/s²

7 0
3 years ago
If the force between two fixed Charged spheres is F and you triple the charge on one sphere and also triple the distance between
mezya [45]
Since the charge has a direct proportionality, the increase will be a factor of three. But, since you triple the distance, which has an inversely squared proportion, it will be 3/9 F or 1/3 F.

*This is all based on the fact that this is true:
F_s = \frac{Kq_1q_2}{r^2}

4 0
4 years ago
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