1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
uysha [10]
3 years ago
9

If you are driving a car with a velocity of -25 m/s and you have an acceleration of -2 m/s^2, are you speeding up or slowing dow

n? Why?
Physics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

Hmmm...

This is a bit tricky

Ok...

Negative Velocity means you're Moving in the Opposite direction....

Negative Acceleration (deceleration) means you're slowing down.

Deceleration would mean slowing down if you were Moving with a Positive velocity.

But In this case...

You're Moving with negative velocity and Negative acceleration...

This simply means that the acceleration and velocity vector are in the same direction....

Its means that...

"YOU'RE SPEEDING UP"

Just that you're doing it in the opposite direction.

Hope this helps.

You might be interested in
What are alkaline earth metals used for?
Tomtit [17]

Answer:

C firework

Explanation:

from Quizlet

6 0
3 years ago
Read 2 more answers
8. An effort force of 15 Newtons is applied to an ideal pulley system to lift up a 16 Newton object. If the effort force is exer
Sonbull [250]

Answer:

the distance that the object is raised above its initial position is 5.625 m.​

Explanation:

Given;

applied effort, E = 15 N

load lifted by the ideal pulley system, L = 16 N

distance moved by the effort, d₁ = 6 m

let the distance moved by the object = d₂

For an ideal machine, the mechanical advantage is equal to the velocity ratio of the machine.

M.A = V.R

M.A = \frac{Load}{Effort} = \frac{L}{E} \\\\V.R = \frac{disatnce \ moved \  by \ the \ effort}{disatnce \ moved \  by \ the \ load} = \frac{d_1}{d_2} \\\\For \ ideal \ machine; \ M.A = V.R\\\\\frac{L}{E} = \frac{d_1}{d_2} \\\\d_2 = \frac{E \times d_1}{L} \\\\d_2 = \frac{15 \times 6}{16} \\\\d_2 = 5.625 \ m

Therefore, the distance that the object is raised above its initial position is 5.625 m.​

3 0
3 years ago
How might what is happening in this image affect the nervous system?
Yuri [45]
There is no image!?...was there meant to be something attached?
7 0
3 years ago
What is quantity?explain.
WARRIOR [948]

Answer:

the amount or number of a material or immaterial thing not usually estimated by spatial measurement

6 0
3 years ago
Read 2 more answers
How many neutrons does element x have if it’s atomic number is 40 and it’s mass number is 82?
Black_prince [1.1K]
The atomic number gives you the number of protons element x has. Since the mass of protons and neutrons are almost similar(around 1 amu), the mass number can be thought of as the sum of protons and neutrons. so if element x whose atomic number is 40 has a mass number of 82, then we know that 42 of those must be neutrons.
4 0
3 years ago
Other questions:
  • How does the density of fluid affect the magnitude of buoyancy acting on an object immersed in it
    14·1 answer
  • Why is ammeter connected in series in an electric circuit?
    15·1 answer
  • Water is made of two hydrogen atoms and one oxygen atom bonded together. Julia is describing how water undergoes a physical chan
    15·2 answers
  • A string of length L= 1.2 m and mass m = 20g is under 400 N of tension, its two ends are fixed. a. How many nodes will you see i
    6·1 answer
  • What are examples of convection currents?
    13·1 answer
  • A motorcycle stunt driver zooms off the end of a cliff at a speed of 41.9 meters per second. If he lands after 1.62 seconds, wha
    5·1 answer
  • The rubber ducky has a mass of 5 grams and a volume of 75 mL. How much water does he displace?
    13·1 answer
  • Which model could represent a neutral atom of boron?
    9·2 answers
  • I aavahva
    9·2 answers
  • Which of the following statements are true of free-
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!